Its electronic confuguration is 2.8.6 so it occupies 3 shells.
Answer:
677.76 g of oxygen needed.
Explanation:
Given data:
Mass of glucose = 635.2 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
Number of moles of glucose:
Number of moles = mass/ molar mass
Number of moles = 635.2 g / 180.156 g/mol
Number of moles = 3.53 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
3.53 : 6×3.53 = 21.18 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 21.18 g × 32 g/mol
Mass = 677.76 g
Answer:
B it has increased slightly
Explanation:I took the test
Mainly around the equator, since it receives the most direct sunlight year round.
