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wel
3 years ago
13

Uranium-238 has a half-life of 4.5 billion years. If Earth is about 4.5 billion years old, which statement is true? A. In about

4.5 billion years, there will be the same amount of uranium-238 as there is today. B. About 4.5 billion years ago, there was half as much uranium-238 as there is today. C. About 4.5 billion years ago, there was twice as much uranium-238 as there is today. hellppppppp mmeeeeeeeee
Physics
2 answers:
padilas [110]3 years ago
8 0
The answer is C. <span>About 4.5 billion years ago, there was twice as much uranium-238 as there is today.</span>
wel3 years ago
3 0

Answer: C. About 4.5 billion years ago, there was twice as much uranium-238 as there is today.

Explanation: Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations.

Half life of a radioactive material is the time taken by the material to decompose to half of its original value.

Thus if Uranium-238 has a half-life of 4.5 billion years, it means it has decomposed to half of its original value and thus about 4.5 billion years ago, there was twice as much uranium-238 as there is today.

In next 4.5 billion years, i.e. after two half lives have passed, the amount of uranium will be one fourth of ts original value.

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guajiro [1.7K]

The correct answer to the question is-  2.2\ \mu C

CALCULATION:

As per the question, the electric field generated by the source charge is 1236  N/C at a distance of 4 m.

Hence , electric field  E =  1236 N/C.

The distance of the point R = 4m

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The electric field produced by a source charge of Q at a distance R is calculated as -

                    Electric field E = \frac{1}{4\pi \epsilon_{0}}\frac{Q}{R^2}

Here, \epsilon_{0} is called the absolute permittivity of the free space.

Hence, the charge of source is calculated as -

                                         Q = E\times 4\pi \epsilon_{0}\times R^2

                                            = 1236\times \frac{1}{9\times 10^9}\times (4)^2\ Coulomb

                                            = 2197.33\times 10^{-9}\ C

                                             = 2.19733\times 10^{-6}\ C

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3 0
3 years ago
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Answer:

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