<u>Answer</u>
D) 3100 Liters
<u>Explanation</u>
To get the volume if the balloon you need to use the combined equation of the low of gases.
P₁V₁/T₁ = P₂V₂/T₂
(20×150)/(27+273) = (1×V₂)/(37+273)
3000/300 = V₂/310
10 = V₂/310
V₂ = 10 × 310
= 3100 Liters
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
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Well, the density of the water is

so i believe that is what the question is asking for :)