1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlad1618 [11]
3 years ago
12

Why is friction important for gymnast working on parallel bars

Physics
1 answer:
igomit [66]3 years ago
8 0
Hey there,
Friction is important to increase the friction between the bars and the gymnast to prevent the gymnast from falling and hurting themselves.

Hope this helps :))

<em>~Top♥</em>
You might be interested in
Which of these is a cultural service—a non material benefit people get from the environment
Firdavs [7]
The answer is Providing national parks
6 0
4 years ago
Read 2 more answers
How is the way that allows us to listen to an AM/FM Radio in our car is different from the wave that allows us to listen to mu
SVETLANKA909090 [29]

Answer:

Well AM/Fm is digitally using soundwaves for cars through signal, which we cant hear without one (radio). Concerts are in real life and use wavelegnths that we hear because it bounces off overytihing.

Explanation:

4 0
2 years ago
Which situation could be considered pseudoscience?
kap26 [50]

In situation #2, students are gathering to record their beliefs regarding a certain pseudoscientific area of horsefeathers.

7 0
3 years ago
Read 2 more answers
The record height of a man to date is 8 feet 11 inches​ (107 inches). If all men had identical body​ types, their weights would
Alisiya [41]

Answer:

679.08 lbs

Explanation:

Here it is given that

m\propto h^3

m_1 = Mass of first person = 175 pounds

h_1 = Height of first person = 70 inches

m_2 = Mass of second person

h_2 = Height of second person = 110 inches

\frac{m_1}{m_2}=\frac{h_1^3}{h_2^3}\\\Rightarrow m_2=\frac{m_1h_2^3}{h_1^3}\\\Rightarrow m_2=\frac{175\times 110^3}{70^3}\\\Rightarrow m_2=679.08\ lb

The weight of the second person would be 679.08 lbs

5 0
4 years ago
Beginning at time t = 0, a student exerts a horizontal force on a box of mass 30 kg, causing it to move at 1.2 m/s toward an ele
Alexandra [31]
Since the initial and the final velocity are just equal, it is implied that the acceleration is zero. This means that the net force acting on the body is also zero. The horizontal force should be equal to the force of friction. The force of friction is equal to the product of the coefficient and the normal force. 
                               

 Ff = (coefficient of friction) x Fn


The normal force is equal to the object's weight if the surface is horizontal.


                               Ff = (0.20) x (30 kg) x (9.8 m/s²)  = 58.8 N
<span>

<span>Thus, the horizontal force exerted must be 58.8 N. 

--------------------------------------


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span></span>
6 0
3 years ago
Other questions:
  • What is three sources of light
    14·2 answers
  • The centers of two 15.0 kg spheres are separated by 3.00 m. The magnitude of the gravitational force between the two spheres is
    10·1 answer
  • The force of gravity acting on a child mass on earth is 190 N what is the child Mass
    10·1 answer
  • What happens to the rock structure during each of type of change?
    5·1 answer
  • A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
    10·1 answer
  • PLEASE help!!
    12·1 answer
  • A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a
    8·1 answer
  • Which lists three organic biological molecules?
    10·1 answer
  • Como se dice casa en náhuatl​
    15·1 answer
  • Something has a mass of 40 kg and a velocity of 1 m/s
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!