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Elden [556K]
3 years ago
7

How many hydrogen atoms are there in all the reactants?

Physics
2 answers:
Alinara [238K]3 years ago
6 0

Answer:

<em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>are</em><em> </em><em>t</em><em>wo hydrogen </em><em>atom</em><em> </em><em>in</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>reactants</em><em>.</em>

11Alexandr11 [23.1K]3 years ago
6 0

Answer:

we can find two hydrogen atom in all the reactants

Explanation:

pill!!

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a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma
ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

p=m.V

Where:

m=45 kg is the mass of the skater

V is the velocity

In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

V_{1}=3 m/s

V_{1}=5 m/s

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

4 0
3 years ago
Read 2 more answers
What is net force?
kramer

Answer:

A. The sum of all the forces acting on an object.

3 0
3 years ago
The data in the table above show how far
Taya2010 [7]

Answer:c

Explanation: because if you work it in a paper it should like lil wit is straight the numbers are going up by 16

6 0
3 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
CHEGG You have two pipes, having the same elevation, connected to each other that transport water. The given density of water is
Yakvenalex [24]

Answer:

P = 0.6814 MPa

Explanation:

For this exercise we must use the Betuliano relation

      P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ rho v₂² + rho g y₂

where we use the subscript 1 for the first pipe and the subscript 2 for the second pipe

indicate that the two pipes are at the same level therefore

        y₁ = y₂

       P₂ = P₁ + ½ ro (v₁² - v₂²)

let's calculate

       P₂ = 13,785 10⁵ + ½ 997 (41,221² - 55,654²)

       P₂ = (13.785 - 6.97) 105

       P₂ = 6.814 10⁵ Pa

let's reduce to Mpa

       P₂ = 6.814 10⁵ Pa (1 MPa / 10⁶ Pa)

       P₂ = 6.814 10-1 MPa

       P = 0.6814 MPa

3 0
3 years ago
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