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2 years ago

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Vector ⃑ has a magnitude of 9.0 m and points 40° east of north. Vector ሬ⃑ has a magnitude of 15.0 m and points 30° north of west

. Find the direction of the sum of the vectors, ⃑ + ሬ⃑, as an angle directed north of west.

1 answer:

Aleks [24]2 years ago

3 0

Answer:

i actually dont know

Explanation:

im no brained

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Joaquin is at rest at the top of a hill on a skateboard. Four seconds later, he reaches the bottom of the hill at a final veloci

Andre45 [30]

Explanation:

Given: Initial Velocity=0

Final Velocity= 20 m/s

Time= 4 s

Accleration: Unknowns

Use kinematic equation

$v _{f} = v _{i} + at$

$20 = 0 + at$

$\frac{20m}{s} = a(4s)$

$a = \frac{5m}{ {s}^{2} }$

so a = 5 m/s^2

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2 years ago

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Answer:

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2 years ago

An electric motor with a 1200 hp output drives a machine with an efficiency of 60%. What is the energy output of the machine per

kirill [66]

Answer:

536,904 J/s

Explanation:

The energy output from motor is the input energy in the machine.

We know that efficiency is percentage energy ouput to energy input, and expressed as

$n=\frac {E_o}{E_i}$

Where n and E represent efficiency and energy respectively, subscripts o and i represent output and input respectively. Since for the machine we have the input energy then the output will be the product of efficiency and input energy

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2 years ago

Light bulb is connected to a 110-V source. What is the resistance of this bulb if it is a 100-W bulb

masya89 [10]

Answer:

<h2>121ohms</h2>

Explanation:

Formula used for calculating power P = current * voltage

P = IV

From ohms law, V = IR where R is the resistance. Substituting V = IR into the formula for calculating power, we will have;

P = IV

P =(V/R)V

P = V²/R

Given parameters

Power rating of the bulb P = 100 Watts

Source voltage V = 110V

Required

Resistance of the bulb R

Substituting the given parameters into the formula for calculating power to get Resistance R;

P = V²/R

100 = 110²/R

R = 110²/100

R = 110 * 110/100

R = 12100/100

R = 121 ohms

<em>Hence, the resistance of this bulb is 121 ohms</em>

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