Answer: M-18
Explanation:
The mass spectra of alcohols often fail to exhibit detectable M peaks but instead show relatively large __M-18___ peaks.
Mass spectroscopy is used to determine the molecular mass and molecular formula of a sample.
When the mass spectra of alcohols do not show detectable M peaks, they show relatively large M-18 peaks.
Answer:
a) 210.3 g/mol
b) 210.2 g/mol
c) 384.5 g/mol
Explanation:
First step we will calculate the molar masses of ; carbon atom, hydrogen atom and oxygen atom in each .
<u> Molar mass of dibenzyl ketone</u>
Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone
= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)
= 210.26926 ≈ 210.3 g/mol
<u> Molar mass of benzil</u>
Molar mass of Benzil = ∑ molar masses of atoms in Benzil
= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) + hydrogen(10) =10(1.00784)
= 210.2262 ≈ 210.2 g/mol
<u>Molar mass of 2,3,4,5-tetraphenylcyclopentadienone</u>
Molar mass = ∑ molar masses of atoms
= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )
≈ 384.5 g/mol
Blue should be added somewhere. , than yellow, lastly red+black
Blue, oxygen+hydrogen, carbon+oxygen.
Answer:
a. 
b. 
c. 
Explanation:
Hello,
a. By applying the given information, one obtains:
b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:
c. Here, the propane's combustion chemical reaction is stated:
This enthalpy of reaction is computed via:
Δ
Finally, since it is done for 20 lb of propane (), the obtainable energy is:
Best regards.
