Answer:
hypergeometric
Step-by-step explanation:
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Passcode: DVM21S
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
I tryed my best to figure out what all of the numbers were. if i got any wrong then please tell me and i will put the right answer in the comments.
1) 3/5= 5/x (cross multiply)
3x=5(5)
3x=25
x= 25/3 -or- 8.33
2) 2/4=x/12<span> (cross multiply</span><span>)
</span> 2(12)=4x
24=4x
6=x
3) 10/x=5/9<span> (cross multiply</span><span>)
10(9)=5x
90=5x
18=x
4) 5/5=x/18</span><span> (cross multiply</span><span>)
5(18)=18x
90=18x
5=x</span>
34-5x+2(x-2)=15 1st get rid of () by distributing the 2.
34-5x+2x-4=15 Now collect like terms.
30-3x=15 Get -3x by itself by subtracting 30 in both sides.
-3x=-15 You want X by itself so divide by -3 on both sides.
x=5
Answer:
0.13591.
Step-by-step explanation:
We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.
We know that z-score tells us that a data point is how many standard deviation above or below mean.
To solve our given problem, we need to find area between z-score of -2 and -1 that is 
.
We will use formula 
to solve our given problem.
Using normal distribution table, we will get:
Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.
