Question

530 mL of CO gas at a pressure of 1.2 atm and a temperature of 17ºC. What is the volume of the gas at 0ºC and 1 atm?

Answer 1

Answer:

598.74 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,  

V₁ = 530 mL

V₂ = ?

P₁ = 1.2 atm

P₂ = 1 atm

T₁ = 17 ºC

T₂ = 0 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (17 + 273.15) K = 290.15 K  

T₂ = (0 + 273.15) K = 273.15 K  

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{1.2}\times {530}}{290.15}=\frac {{1}\times {V_2}}{273.15}$

Solving for V₂ , we get:

V₂ = 598.74 mL