Answer:
3.9 laps
Explanation:
Step 1: Given data
Length of the hamster track (L): 255 cm
Total distance to be run (D): 10 m
Step 2: Convert "D" to centimeters
We will use the relationship 1 m = 100 cm.
10 m × (100 cm/1 m) = 1.0 × 10³ cm
Step 3: Calculate the number of laps (n) that the hamster should run
We will use the following expression.
n = D/L
n = 1.0 × 10³ cm/255 cm
n = 3.9
PH = -log[H+]
That is, pH is the negative logarithm of the hydrogen ion concentration.
pOH = -log[OH-]
pOH is the negative logarithm of the hydroxide ion concentration.
The correct answer to your question is a. The negative logarithm of the hydrogen ion concentration.
Answer:
44.91% of Oxygen in Iron (III) hydroxide
Explanation:
To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:
<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>
<em />
<em>Molar mass Fe(OH)3 and oxygen:</em>
1Fe = 55.845g/mol*1 = 55.845
3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen
3H = 1.008g/mol*3 = 3.024
55.845 + 48.00 + 3.024 =
106.869g/mol is molar mass of Fe(OH)3
% Composition of oxygen is:
48.00g/mol / 106.869g/mol * 100 =
<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
Answer:
The density of ozone is 4.24.
Explanation:
The relation between the relative rate of diffusion and density is given by :
The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.
Let the density of ozone is d₂.
So, the density of ozone is 4.24.
