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bezimeni [28]
3 years ago
14

What element has the smallest atomic radius

Chemistry
1 answer:
Mariulka [41]3 years ago
4 0
Helium has the smallest atomic radius® Α⇒Ω
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One lap of an engineered hamster track measures 255 cm. To run 10. meters, how many laps should the hamster run? Report your ans
Maru [420]

Answer:

3.9 laps

Explanation:

Step 1: Given data

Length of the hamster track (L): 255 cm

Total distance to be run (D): 10 m

Step 2: Convert "D" to centimeters

We will use the relationship 1 m = 100 cm.

10 m × (100 cm/1 m) = 1.0 × 10³ cm

Step 3: Calculate the number of laps (n) that the hamster should run

We will use the following expression.

n = D/L

n = 1.0 × 10³ cm/255 cm

n = 3.9

4 0
3 years ago
What is pH?
sergij07 [2.7K]
PH = -log[H+]
That is, pH is the negative logarithm of the hydrogen ion concentration.

pOH = -log[OH-]
pOH is the negative logarithm of the hydroxide ion concentration.

The correct answer to your question is a. The negative logarithm of the hydrogen ion concentration.
5 0
3 years ago
What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH)<br> 3?
S_A_V [24]

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>

<em />

<em>Molar mass Fe(OH)3 and oxygen:</em>

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
7 0
2 years ago
Give the % composition for each element found in tin (IV) nitride.
drek231 [11]

32.3699% Tin (Sn)

15.2774% Nitrogen (N)

52.3527% Oxygen (O)

4 0
2 years ago
If the relative rate of diffusion of ozone as compared to chlorine is 6:3 and further if the density of chlorine is 36 Find out
Alexandra [31]

Answer:

The density of ozone is 4.24.

Explanation:

The relation between the relative rate of diffusion and density is given by :

r\propto \dfrac{1}{\sqrt d}

The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.

Let the density of ozone is d₂.

\dfrac{r_1}{r_2}=\sqrt{\dfrac{d_2}{d_1}} \\\\\dfrac{6}{3}=\sqrt{\dfrac{d_2}{36}} \\\\3=\dfrac{\sqrt{d_2}}{6}\\\\d_2=\sqrt{18} \\\\d_2=4.24

So, the density of ozone is 4.24.

6 0
2 years ago
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