Question

Solve this problem using the above process. The sides of a triangular lot are represented by x, 3x, and 3x + 2. Find each side if the perimeter is 632 feet. The first length is The second length is The third length is

Answer 1

Answer: The first length is x =90 feet

The second length is 3x=270 feet

The third length is 3x+2 =272 feet

Step-by-step explanation:

Given: The sides of a triangular lot are represented by x, 3x, and 3x + 2.

The perimeter of the triangular lot = 632 feet

We know that the perimeter of any polygon is the sum of all its sides.

Thus, we have

$x+3x+3x+2=632\\\\\Rightarrow\ 7x+2=632\\\\\Rightarrow\ 7x=630\\\\\Rightarrow\ x=90\ feet$

Now, the first length is x =90 feet

The second length is 3x=$3\cdot90=270\ feet$

The third length is 3x+2 =$3\cdot90+2=270+2=272\ feet$

Answer 2

We have 3 sides
x,3x,3x+2
P=632
x+3x+3x+2=632
7x=632-2
7x=630
x=90
3x=270
3x+2=272