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3 years ago

What does erosion do to landforms and to sediment

2 answers:

5 0

For example imagine a cliff near the ocean and the waves keep hitting it thats a landform and erosion happening erosion breaks sediment down

snow_tiger [21]3 years ago

5 0

Well it breaks it away from rain or earthqukes depends but then depostion takes the rocks away and a delta takes it into the ocean

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Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are

Contact [7]

Answer:

r=0.127

Explanation:

When connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

In series R = R₁+R₂

in parallel R= R₁R₂/(R₂+ R₁)

Given that voltage is constant (Vo)

V = I R

Vo = I (R₁+R₂) ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)

10 R₁R₂ = (R₁+R₂) (R₂+ R₁)

10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²

8 R₁R₂ = R₁² + R₂²

Given that

r = R₁/R₂

Divides by R₂²

8R₁/R₂ = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0

r= 0.127 and r= 7.87

But given that R₂>R₁ It means that r<1 only.

So the answer is r=0.127

8 0

4 years ago

A horizontal pipe of inner diameter 2.2 cm carries water with a density of 1000.0 kg/m3 flowing at a rate of 1.5 kg/s. If the pi

EleoNora [17]

The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.

<h3> What is speed?</h3>

Speed is defined as the rate of change of the distance or the height attained.

The given data in the problem is;

The initial diameter is, $\rm d_1 = 2.2 \ cm$

initial radius,

$r_1 = \frac{d_1}{2} \\\\ r_1 = \frac{2.2}{2} \\\\ r_1 = 1.1\ cm$

The initial crossection area;

$\rm A_1 = \pi r_1^2 \\\\ \rm A_1 = 3.14 \times (1.1\times 10^{-2})^2 \\\\ \rm A_1 =3.8 \times 10^{-4} \ m^2$

The final crossection area;

$\rm A_2 = \pi r_2^2 \\\\ \rm A_2 = 3.14 \times ( 2 \times 10^{-2})^2 \\\\ \rm A_2 = 12.56 \ m^2$

The initial flow rate is;

R = density ×velocity ×area

$\rm R = \rho A V \\\\ 1.5 = 1000 \times V_1 \times 3.8 \times 10^{-4} \\\\ V_1 = 3.947 \ m/sec$

The speed of the water in the wider part will be;

From the continuity equation;

$\rm A_1 V_1 = A_2V_2 \\\\\ 3.8 \times 10^{-4} \times 3.947 = 12.56 \times 10^{-4} \times V_2 \\\\ V_2= 1.194 \ m/sec$

Hence, the speed of the water in the wider part will be 1.194 m/sec.

To learn more about the speed, refer to the link;

brainly.com/question/7359669

#SPJ1

7 0

2 years ago

What is the resultant of the vectors shown?

adelina 88 [10]

the one with the big mustard-colored stripe across it is the correct choice.

6 0

3 years ago

Read 2 more answers

What is solubility? (8th grade science)

lutik1710 [3]

The ability to be dissolved, especially in water.

5 0

3 years ago

TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accele

Novay_Z [31]

Answer:

True

Explanation:

Speed = distance/time

If distance and time are the same, then the right hand side of the equation remains the same, causing us to solve the left to the same value

As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)

8 0

3 years ago