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Nastasia [14]
3 years ago
12

Can somebody plz answer these 3 questions correct

Chemistry
2 answers:
marishachu [46]3 years ago
6 0

Answer:

11. I think the answer is, Both humans and whale embryos have a tail and a backbone (I'm not sure).

12. Basilosaurid, any member of the family Basilosauridae, an early group of whales that lived from the middle Eocene to the late Oligocene Epoch (about 41 million to 23 million years ago).

13.  Protocetids had long snouts, large eyes, and their nasal opening was farther caudally than in earlier archaeocetes.

Hope this helps! :D

Travka [436]3 years ago
5 0

Answer: Basilosaurus is a prehistoric whale which lived approximately 40 million to 34 million years ago during the Late Eocene Period.

Explanation:

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What is the average binding energy per nucleon for a U-238 nucleus with a mass defect of 0.184 amu? (1 amu= 1.66 x 10-27 kg; 1 J
Bond [772]

add all the number and find the average then subtract the mass defect and then you will get your answer

3 0
3 years ago
A device that sends electrical impulses to the heart to correct an irregular
IgorC [24]
A. A pacemaker

Hope this helps!
6 0
2 years ago
A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?
nataly862011 [7]

Answer:

Na

Explanation:

8 0
3 years ago
How many moles are in 7.6 g of Ca
klasskru [66]

Your answer would be 0.024951344877489 but rounding it would be 0.025 moles

7 0
3 years ago
Using the Bohr model, determine the energy, in joules, necessary to ionize a ground-state hydrogen atom. Show your calculations.
lord [1]

Answer:

The energy required to ionize the ground-state hydrogen atom is 2.18 x 10^-18 J or 13.6 eV.

Explanation:

To find the energy required to ionize ground-state hydrogen atom first we calculate the wavelength of photon required for this operation.

It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

n1 = initial state = 1 (ground-state of hydrogen)

n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

λ = 9.115 x 10^-8 m = 91.15 nm

Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

Therefore,

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

<u>E = 2.18 x 10^-18 J</u>

E = (2.18 x 10^-18 J)(1 eV/1.6 x 10^-19 J)

<u>E = 13.6 eV</u>

5 0
3 years ago
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