<span>homogeneous because particles are mixed uniformly</span>
Answer:
<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>
Explanation:
Since
is a weak acid to find the pH of
we use the formula

where
Ka is the acid dissociation constant
c is the concentration
From the question
Ka of
= 1.75 × 10^-5
c = 1.00 × 10-³M
Substitute the values into the above formula and solve for the pH
That's

We have the answer as
<h3>pH = 3.9</h3>
To find the pOH we use the formula
pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 3.9
We have the answer as
<h3>pOH = 10.1</h3>
Hope this helps you
<span>35.0 mL of 0.210 M
KOH
molarity = moles/volume
find moles of OH
do the same thing for: 50.0 mL of 0.210 M HClO(aq) but for H+
they will cancel out: H+ + OH- -> H2O
but you'll have some left over,
pH=-log[H+]
pOH
=-log[OH-]
pH+pOH
=14</span>
I think it’s B because I just know