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omeli [17]
3 years ago
10

The alchemists were the first to do what?

Chemistry
1 answer:
Bezzdna [24]3 years ago
8 0
Alchemists attempted to purify, mature, and perfect certain materials. ... Islamic and European alchemists developed a structure of basic laboratory techniques, theory, terminology, and experimental method, some of which are still in use today.
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How would you prepare 3.5 L of a 0.9M solution of KCl?
PolarNik [594]
V=3,5L\\
Cm=0,9M\\
M_{KCl}=74\frac{g}{mol}\\\\
C_{m}=\frac{n}{V}\\\\
n=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV} \ \ \ \Rightarrow  \ \ \ m=C_{m}MV\\\\
m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark. 
4 0
3 years ago
A small cylinder of helium gas used for filling balloons has a volume of 2.20 L and a pressure of 14300 kPa at 25 ∘C. Part A How
Korvikt [17]

Answer:

You can fill 212 balloons.

Explanation:

First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>

  • P =  14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
  • V = 2.20 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • n = 12.70 mol

Then we <u>calculate the number of moles that can fit in a single balloon</u>:

  • 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
  • n = 0.0599 mol

Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:

  • 12.70 mol / 0.0599 mol = 212.09

So the answer is that you can fill 212 balloons.

7 0
3 years ago
Pls help this is science pls help
Sloan [31]
The top left image is a delta, which is caused by deposition.
The top middle image is a lake, which is caused by erosion.
The bottom left is a mountain, which is caused by plate tectonics.
The bottom middle is a volcano, which is caused by uplift.
4 0
4 years ago
MARKING BRAINLIEST AND 16 POINTS!
Hitman42 [59]

Answer:

i think its A

Explanation:

bc the nucleus is the very center of whatever the organism is.

8 0
3 years ago
A 0.2121g sample of an organic compound was burned in a stream of oxygen and the carbon dioxide produced was collected in a stre
pav-90 [236]

Answer:

The answer to your question is: 17.26% of carbon

Explanation:

Data

CxHy = 0.2121 g

BaCO₃ = 0.6006 g

Molecular mass BaCO₃ = 137 + 12 + 48 = 197 g

Reaction

                    CO₂  +  Ba(OH)₂  ⇒   BaCO₃  +  H₂O

Process

1.- Find the amount of carbon in BaCO₃

                              197 g of BaCO₃   ---------------  12 g of Carbon

                               0.6006 g           ----------------    x

                               x = (0.6006 x 12) / 197

                               x = 0.0366 g of carbon

2.- Calculate the percentage of carbon in the organic compound

           0.2121 g of organic compound  ---------------  100%

           0.0366g                                       --------------    x

                              x = (0.0366 x 100) / 0.2121

                              x = 17.26%

4 0
3 years ago
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