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Eduardwww [97]
3 years ago
7

Compare and contrast granite and rhyolite

Chemistry
2 answers:
tester [92]3 years ago
8 0
Hey there!
Great question=)

Answer: Contrast-Same chemical composition. Granite is intrusive, when rhyolite is extrusive!
Compare-Different cooling rates.

<span>I hope this helps;)</span>
Alona [7]3 years ago
5 0

Answer:

Explanation:

Hello,

In this case, we say that rhyolite is very closely related to granite, nonetheless rhyolite has a larger a mount of finer crystals than granite, which are as tiny as they are not possible to be seen by a simple look with out eyes. Moreover, rhyolite is an extrusive igneous rock that was formed by cooling down more rapidly than granite which provide it a glassy glance. Additionally, rhyolite is made up of quartz, feldspar, mica, and hornblende.

On the other hand, the granite is a shiny-like igneous rock with visible grans by a simple look (unlike rhyolite). It is formed when a sluggish crystallization of magma is carried out underground. It is majorly made up of quartz and feldspar with traces of mica, amphiboles, and other minerals.

Best regards.

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2 years ago
Using the systematic approach for equilibrium problems, calculate the pH of 0.05 M HOCl. Ka= 3.0*10-8 Group of answer choices 3.
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Answer:

The pH is equal to 4.41

Explanation:

Since HClO is a weak acid, its dissociation in aqueous medium is:

                HClO   ⇄   ClO-  +  H+

start:          0.05            0         0

change       -x               +x       +x

balance     0.05-x         x         x

As it is a weak acid it dissociates very little, in its ClO- and H + ions, so the change is negative, where x is a degree of dissociation.

the acidity constant when equilibrium is reached is equal to:

Ka=\frac{[ClO-]*[H+]}{[HClO]}=\frac{x*x}{0.05-x}=3x10^{-8}

The 0.05-x fraction can be approximated to 0.05, because the ionized fraction (x) is very small, therefore we have:

3x10^{-8}=\frac{x^{2} }{0.05}

clearing the x and calculating its value we have:

x=3.87x10^{-5}=[H+]=[ClO-]

the pH can be calculated by:

pH=-log[H+]=-log[3.87x10^{-5}]=4.41

7 0
3 years ago
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