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morpeh [17]
4 years ago
12

A 2kg ball is thrown upward with a velocity of 15 m/s what is the kinetic energy of the ball being thrown?

Physics
1 answer:
vivado [14]4 years ago
7 0
Kinetic Energy, or K.E is equal to 1/2 times the mass of an object times the velocity squared.

Therefore K.E
=  \frac{1}{2}  \times 2 \times  {15}^{2}
which is 225

Energy is expressed in joules (J)
so the K.E of the ball is 225J

Hope this helped
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a 2kg object is moving horizontally with a speed of 4 m/s.how much net force is required to keep the object moving at this speed
Elza [17]
If the object is moving in a straight line with constant speed,
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8 0
4 years ago
The Cartesian coordinate of a point in the xy plane are (x,y)=(-3.50,-2.50)m. Find the poler coordinate of this point
Masja [62]

Answer:

The polar coordinate of P(x,y) = (-3.50\,m,-2.50\,m) is P (r,\theta) = (4.301\,m, 215.538^{\circ}).

Explanation:

Given a point in rectangular form, that is P(x,y) = (x,y), its polar form is defined by:

P(x,y) = (r,\theta) (1)

Where:

r - Norm, measured in meters.

\theta - Direction, measured in sexagesimal degrees.

The norm of the point is determined by Pythagorean Theorem:

r = \sqrt{x^{2}+y^{2}} (2)

And direction is calculated by following trigonometric relation:

\theta = \tan^{-1} \frac{y}{x} (3)

If we know that x = -3.50\,m and y = -2.50\,m, then the components of coordinates in polar form is:

r = \sqrt{(-3.50\,m)^{2}+(-2.50\,m)^{2}}

r \approx 4.301\,m

Since x < 0\,m and y < 0\,m, direction is located at 3rd Quadrant. Given that tangent function has a period of 180º, we find direction by using this formula:

\theta = 180^{\circ}+\tan^{-1} \left(\frac{-2.50\,m}{-3.50\,m} \right)

\theta \approx 215.538^{\circ}

The polar coordinate of P(x,y) = (-3.50\,m,-2.50\,m) is P (r,\theta) = (4.301\,m, 215.538^{\circ}).

5 0
3 years ago
According to the law of refraction, light passing from air into a piece of glass at an angle of 30 degrees will cause the light
pantera1 [17]

Answer:

bend toward the normal line

Explanation:

When light passes from a less dense to a more dense substance, (for example passing from air into water), the light is refracted (or bent) towards the normal.   In your question the light is moving from rarer to denser medium

4 0
4 years ago
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