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Brut [27]
4 years ago
14

Molly and James tracked the average temperature in their city for the past 8 days. They recorded their temperature findings in t

his list. 74°F , 79°F , 76°F, 85°F, 87°F, 83°F, 86°F, 78°F What is the mean absolute deviation of this data set? Enter your answer in the box.
Please help me I will give out extrapoints
Mathematics
1 answer:
Katyanochek1 [597]4 years ago
5 0
Add all the numbers then divde by how many numbers there are so the total divde by 8
You might be interested in
The probability that a randomly chosen person has a dog is 0.34. The probability that a randomly chosen person will have a dog a
Elina [12.6K]

Taking into definition of probability, the probability that a randomly chosen person is not walking in the park is 0.91.

<h3>Definition of Probabitity</h3>

Probability is the possibility that a phenomenon or an event will happen, given certain circumstances. It is expressed as a percentage.

<h3>Union of events</h3>

The union of events, AUB, is the event formed by all the elements of A and B. That is, the event AUB is verified when one of the two, A or B, or both occurs. AUB is read as "A or B".

The probability of the union of two compatible events is calculated as the sum of their probabilities subtracting the probability of their intersection:

P(A∪B)= P(A) + P(B) -P(A∩B)

<h3>Complementary event</h3>

A complementary event is made up of the inverse of the results of another event. That is, That is, given an event A, a complementary event is verified as long as the event A is not verified.

The probability of occurrence of the complementary event A' will be:

P(A´)= 1- P(A)

<h3>Events and probability in this case</h3>

In first place, let's define the following events:

  • D: a person has a dog.
  • W: a person is walking in the park.

Then you know:

  • P(D)= 0.34
  • P(D and W)= P(D∩W)= 0.03 [The intersection of events, A ∩ B, is the event formed by all the elements that are, at the same time, from A and B. That is, the event A ∩ B is verified when A and B occur simultaneously.]
  • P(D or W)= P(D∪W)= 0.40

In this case, considering the definition of union of eventes, the probability that a randomly chosen person is walking in the park is calculated as:

P(D∪W)= P(D) + P(W) -P(D∩W)

0.40= 0.34 + P(W) -0.03

Solving:

0.40= 0.31 + P(W)

0.40 - 0.31= P(W)

<u><em>0.09= P(W)</em></u>

Then, the probability that a randomly chosen person is walking in the park is 0.09.

Considering the definition of the complementary event and its probability, the probability that a randomly chosen person is NOT walking in the park is calculated as:

P [W']= 1- P(W)

Replacing and solving:

P [W']= 1 - 0.09

P [W']= 0.91

Finally, the probability that a randomly chosen person is not walking in the park is 0.91.

Learn more about probability:

brainly.com/question/25839839

brainly.com/question/26038361

#SPJ1

7 0
2 years ago
PLEASE HELP ASAPP!!!
amid [387]

Answer:

3/5

Step-by-step explanation:

3 and 4 and 5 are more than 2 so they are 3 quantities and the total of the quantities are 5 so the answer should be 3/5

5 0
4 years ago
A laboratory animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one
taurus [48]

Answer:

P= \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

Step-by-step explanation:

let a, b and c be the type of foods used in trail.

Example matrix combination for (1,1) is (a,a) is 0.5. Another Example for (1,2) is (a,b) is 0.25.

The diagonals are (a,a), (b,b) and (c,c) which means same food in two trails and its probability is 0.5. the rest would be 0.25

Therefore, stochastic matrix would have 3 by 3 matrix such as (a,a), (a,b) .... (c,c)

\left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right] \\

3 0
3 years ago
Please help me with this problem I need your help badly
Lelechka [254]


8.223 inches.

38.000
-29.777
8.223
7 0
3 years ago
Please help i will give brainliest
RideAnS [48]
The answer would be C because it’s the only fraction that does not equal 0.4
8 0
3 years ago
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