3 years ago

Use the Divergence Theorem to calculate the surface integral

1 answer:

3 0

Divergense theorem says flux across the closed surface = ∫∫∫ div F dV

div F = 3y^2+ 3 z^2 
convert to cylindrical 
y = r cos t 
z = r sin t 
x = x 
dx dy dz = r dx dr dt 

∫ [0, 2pi]∫[0,3]∫ [-1,3] 3r^3 dx dr dt 

2pi(3)(81/4)(4) 
486pi

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