Answer:
122.76J
Explanation:
Given data
work done= 372 Joules
efficiency= 33%
Required
We want to compute the value of the work that is 33%
= 33/100* 372
= 0.33*372
= 122.76J
Hence 122.76J of work is transferred from the engine to the exhaust
Answer:
2.04m/s²
Explanation:
Complete Question
<em>A stationary 10 kg object is located on a table near the surface of the earth. The coefficient of kinetic friction between the surfaces is 0.2. A horizontal force of 40 N is applied to the object. Find the acceleration of the object.</em>
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According to Newtons second law;
\sum F_x = ma_x
F_m - F_f = ma_x
Fm is the applied force
Ff is the frictional force
m is the mass
a is the acceleration
Substitute the given values
40N - nmg = 10a
40 - 0.2(10)(9.8) = 10a
40 - 19.6 = 10a
20.4 = 10a
a = 20.4/10
a = 2.04m/s²
<em>Hence the acceleration of the object is 2.04m/s²</em>
The change in temperature here corresponds to a sensible heat. The amount of energy required can be calculated by multiplying the specific heat capacity, the amount of the substance and the corresponding change in temperature.
Heat required = mCΔT
Heat required = 0.368 kg (0.0920 cal/g°C) (60 - 23)°C
Heat required = 1.25 cal
Answer:
The system will tend to person A
Explanation:
A force is defined as either a pull or a push, in this scenario person A weighs lass that person B, so the resultant effect of the 10N interactive force will tend towards person A.
This is solely because person A is less than person B in weigh
Answer:
the gravitational potential energy is converted to kinetic energy
Explanation:
Because the conversation of the energy as a tool permits the calculation of the velocity just before it hits the surface