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vitfil [10]
3 years ago
9

If you find the mass of a sample to be 42.1 g and the actual mass is 42.0 g. What wold be the percent error

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

0.24%

Explanation:

The following data were obtained from the question:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error can be obtained by using the following formula:

Percentage error = |Measured value – Actual value | / Actual value × 100

With the above formula, we can obtain the percentage error as follow:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error = |42.1 – 42| / 42 × 100

Percentage error = 0.1/42 × 100

Percentage error = 10/42

Percentage error = 0.24%

Therefore, the percentage error is 0.24%

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A) When the temperature inside the container increases, the pressure inside the container increases as well. 

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This law was formulated by the famous French chemist that gives it its name. It relates the expansion of a gas with the increase in temperature when the volume is left constant. The Gay-Lussac's Law can be expressed as follows, for the case of this exercise:

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Answer:

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The total time = 4.76\times 60=286minutes

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