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vitfil [10]
3 years ago
9

If you find the mass of a sample to be 42.1 g and the actual mass is 42.0 g. What wold be the percent error

Chemistry
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

0.24%

Explanation:

The following data were obtained from the question:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error can be obtained by using the following formula:

Percentage error = |Measured value – Actual value | / Actual value × 100

With the above formula, we can obtain the percentage error as follow:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error = |42.1 – 42| / 42 × 100

Percentage error = 0.1/42 × 100

Percentage error = 10/42

Percentage error = 0.24%

Therefore, the percentage error is 0.24%

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Answer:

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7 0
3 years ago
What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

       = 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


∴ mass = 0.68 moles* 120 g/mol = 81.6 g
7 0
3 years ago
47.0ml of a HBr solution were titrated with 37.5ml of a 0.215M LiOH solution to reach the equivalence point. what is the molarit
faltersainse [42]

Hello!

The molarity of the HBr solution is 0,172 M.

Why?

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

To solve this exercise, we are going to apply the common titration equation:

M1*V1=M2*V2

M1=\frac{M2*V2}{V1}= \frac{0,215 M * 37,5 mL}{47 mL}=0,172 M

Have a nice day!

4 0
4 years ago
Please help!!!!!!!!!!
STatiana [176]
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal

Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal

Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal

Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal

Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal

sorry i don’t know about the other questions but i thought i could help with the table!

Additional Info:

number of protons = atomic number

number of electrons = atomic number

number of neutrons = mass number - atomic number
3 0
3 years ago
If the density of D-2 diesel fuel is 55.0 lb/ft3, what is the mass of fuel in kilograms when a tank with volume 19.7 is full?
DaniilM [7]

Answer:24.9

Explanation:

6 0
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