Jen runs 1/8 of a mile before tennis practice.How many feet does she run before practice?

The midpoint of AB is M(4,-2). If the coordinates of A are (3, -6), what are the

satela [25.4K]

Answer:

okay here we go

Step-by-step explanation:

$in \: vectos \: ab \: means \: ob - oa \\ but \: the \: midpoint \: m \: is \: equal \: to \: a \: half \: of \: ab \\ \\ therefore \: m = \frac{1}{2} ab \\ = \frac{1}{2} (ob - oa) \\ = \frac{1}{2} (ob - (3. - 6)) \\ (4. - 2) = \frac{1}{2} (ob - (3. - 6)) \\ (8. - 4) = (ob - (3. - 6)) \\ ob = (11. - 2)$

5 0

2 years ago

Can someone simplify

Rashid [163]

Answer:

Option (2). $2\frac{1}{4}$

Step-by-step explanation:

The given expression is [ $-5\frac{1}{4}-(-7\frac{1}{2})$ ]

We can rewrite the fractions as,

$-5\frac{1}{4}$ = $-(5+\frac{1}{4})$

$-7\frac{1}{2}=-(7+\frac{1}{2})$

Now we will substitute the fractions in the expression,

$[-(5+\frac{1}{4})]-[-(7+\frac{1}{2})]$

= $-(5+\frac{1}{4})+(7+\frac{1}{2})$

= (-5 + 7) + $(-\frac{1}{4}+\frac{1}{2})$

= 2 + $\frac{2-1}{4}$

= 2 + $\frac{1}{4}$

= $2\frac{1}{4}$

Therefore, Option (2). will be the answer.

7 0

3 years ago

What are a) the ratio of the perimeter’s b) and the ratio of areas of the larger figure to the smaller figure?

GREYUIT [131]

a) We have been given two similar figures and we have to find ratio of perimeters of these figures.

Let a be given side of larger figure and b be the given side of smaller figure. Let $p_{1} \text{ and } p_{2}$ be the perimeters of two figures and $A_{1} \text{ and } A_{2}$ be the areas of the two figures.

We know that perimeters of two similar figures are in the ratio of corresponding sides.

$\frac{p_{1}}{p_{2}}=\frac{a}{b}$

We have been given, $a=26\text{ and }b=6$

Therefore, upon substituting these values in the above equation, we get

$\frac{p_{1}}{p_{2}}=\frac{26}{6}$

$\frac{p_{1}}{p_{2}}=\frac{13}{3}$

(b)

Further we know that areas of two similar figures are in the ratio of squares of corresponding sides.

$\frac{A_{1}}{A_{2}}=\frac{a^{2}}{b^{2}}\\
\frac{A_{1}}{A_{2}}=\frac{26^{2}}{6^{2}}\\
\frac{A_{1}}{A_{2}}=\frac{676}{36}\\
\frac{A_{1}}{A_{2}}=\frac{169}{9}\\$

Therefore, first option is the correct answer.

3 0

3 years ago

Read 2 more answers

Michael made a baby quilt that was 3 feet wide. Its Perimeter was 16 feet what was its Area. Show me the steps. Thanks

PtichkaEL [24]

You know that 2 sides are 3 feet, if the said baby quilt is a rectangle. Anyway, 2(of the sides) x 3 = 6. So that's 6 of the 16 feet of the perimeter. The other sides added together is 10, and since you have to split 10 in 2, the other sides are 5 feet each. So you have 5+5+3+3=16. Now you take two side that are perpendicular to each other(one 5 feet and another 3 feet) and multiply them. 3x5=15. So the area is 15 feet squared.

4 0

3 years ago

Read 2 more answers

Annabelle and Navene are multiplying (4^2 7^5) (4^3 7^2)

Brums [2.3K]

4^2=16
7^5=<span>16807
4^3=64
7^2=49
When all multiplied together equals </span><span>843308032.</span>

3 0

3 years ago