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taurus [48]
3 years ago
13

What is the vertex of the quadratic function f(x) = (x - 3)(x - 2)? D

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

Step-by-step explanation:

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.

- that's how you find the vertex of the quadratic function-

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A mountain is in the shape of a cone whose height is about 3.7 kilometers and whose base radius is about 3 kilometers. Approxima
Lelu [443]

Answer:

34.54 km^{3}

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Height (h) = 3.7 km

Base radius (r) = 3 km

We can calculate the volume of mountain by using following formula,

So, volume of cone = (1/3)πr^{2}h

By putting the value in the formula, we get

= (1/3) π × 3^{2} × 3.7

= 11.1π

= 34.54 km^{3}

Hence, the volume of the mountain is  34.54 km^{3}.

7 0
3 years ago
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
Piano lessons cost $15. What expressions could be used to find the cost in dollars of 5 lessons
kirill115 [55]
Just write 15x5. Hope I helped
5 0
3 years ago
Help me please!!!!!!!!!!!!!!!!
AVprozaik [17]

Answer: idk but i will look

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Factorise fully X^2 subtract 2x
anastassius [24]

Answer:

x(x-2)

Step-by-step explanation:

X^2-2x

x(x-2)

7 0
3 years ago
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