three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650
Solar system is nested nearly 2/3 of the way from the center of the galaxy to the outskirt of the galactic disc.
Back emf is 85.9 V.
<u>Explanation:</u>
Given-
Resistance, R = 3.75Ω
Current, I = 9.1 A
Supply Voltage, V = 120 V
Back emf = ?
Assumption - There is no effects of inductance.
A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.
So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,
The voltage across the resistance would be
v = I x R
= 9.1 x 3.75
= 34.125 volts
We know,
supply voltage = back emf + voltage across the resistance
By plugging in the values,
120 V = back emf + 34.125 V
Back emf = 120 - 34.125
= 85.9 Volts
Therefore, back emf is 85.9 V.
Answer:
Option D. 1000 J.
Explanation:
From the question given above, the following data were obtained:
Force (F) applied = 200 N
Distance (s) = 5 m
Time (t) = 10 s
Workdone (Wd) =?
Workdone (Wd) is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:
Wd = F × s
With the above formula, we can calculate the Workdone as illustrated below:
Force (F) applied = 200 N
Distance (s) = 5 m
Workdone (Wd) =?
Wd = F × s
Wd = 200 × 5
Wd = 1000 J
Thus, the Workdone is 1000 J
It is D. An object can acquire a net charge only when charges are transferred to or from it.
