<span>Unless the pig moves static friction acts on it once the pig starts moving kinetic friction comes in to play so when the pig is not moving=frictional force acting on it =normal force*co-efficient of static friction.</span>
Answer:
There are two ways we may, one day, be able to time travel forwards.
You may have heard of Cryogenics. This is when someone who’s died is frozen instead of being buried or cremated. The theory is they can be “woken up” in the future when we have the technology to bring them back to life. Or a machine or device could be developed so that some people age more slowly than others around them. This way they’d live longer and see a future beyond the average person’s life span.
Another very different way of travelling into the future is more like what you’d see in science fiction. This is might involve travelling in a rocket or spaceship at a very high speed, close to the speed of light. “We can’t establish equality with the speed of light but it is possible, in theory, to travel nearly as fast as the speed of light,” adds Dr Steane.
So imagine you’re in a spaceship travelling very fast away from the Earth and you stay in orbit for a year. You would age at the same rate as if you were still on the Earth, by a year, but when you returned, the earth may have aged hundreds of years. “This is way beyond the technology we have at the moment,” he says. “But... in theory, it is possible.”
Explanation:
Hope this helped!
Answer:
Transferred material is in the same relative position on the disk as on the original sample
Explanation:
The usefulness of blotting techniques in molecular biology is that transferred material is in the same relative position on the disk as on the original sample
Answer:
a) 
b) the motorcycle travels 155 m
Explanation:
Let 
, then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):
where:
is the speed of the motorcycle at time 2
is the velocity of the car (constant)
is the velocity of the car and the motorcycle at time 1
d is the distance between the car and the motorcycle at time 1
x is the distance traveled by the car between time 1 and time 2
Solving the system of equations:
![\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dcar%26motorcycle%5C%5Cx%3Dv_0%5CDelta%7Bt%7D%26x%2Bd%3D%28%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%7D%29%20%5CDelta%7Bt%7D%5Cend%7Barray%7D%5Cright%5D)
For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:
