Answer:
513.975g
Explanation:
I'm assuming that the question has Aluminium and Chlorine as the question is not clear.
1. Balance the equation
2 Al + 3 Cl2 → 2AlCl3
2. Use the mole = mass/mr equation and molar ratio to find the mass of AlCl3
133.5 x 3.85 = 513.975g
Answer:
V₂ = V₁ / T₁ * T₂ . If you prefer to set the final volume and want to estimate the resulting temperature, then the equation of Charles' law changes to: T2=T1/T1 multiplied by v^2.
