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siniylev [52]
3 years ago
12

An FM radio station broadcast at a frequency of 98.5 MHz. What is the wavelength of the station’s broadcast signal?

Chemistry
1 answer:
Troyanec [42]3 years ago
4 0

Answer:

(1 MHz = 106 s -1)

Explanation:

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What is the name of the configuration management procedure that involves the collection of information about a system under norm
raketka [301]

The name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

<h3>What is Baselining?</h3>

Baselining is a management process used to analyze a collection of information about a particular system.

This procedure (Baselining) is well known to analyze computer performance in a given network.

In conclusion, the name of the configuration management procedure that involves the collection of information about a system under normal operating conditions is Baselining.

Learn more about Baselining here:

brainly.com/question/25836560

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5 0
2 years ago
The enzyme, phosphoglucomutase, catalyzes the interconversion
Fittoniya [83]

Answer:

K_{eq = 19

ΔG° of the reaction forming glucose 6-phosphate =  -7295.06 J

ΔG° of the reaction  under cellular conditions = 10817.46 J

Explanation:

Glucose 1-phosphate     ⇄     Glucose 6-phosphate

Given that: at equilibrium, 95% glucose 6-phospate is  present, that implies that we 5% for glucose 1-phosphate

So, the equilibrium constant K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq= \frac{0.95}{0.05}

K_{eq = 19

The formula for calculating ΔG° is shown below as:

ΔG° = - RTinK

ΔG° = - (8.314 Jmol⁻¹ k⁻¹ × 298 k ×  1n(19))

ΔG° = 7295.05957 J

ΔG°≅ - 7295.06 J

b)

Given that; the concentration  for  glucose 1-phosphate = 1.090 x 10⁻² M

the concentration of glucose 6-phosphate is 1.395 x 10⁻⁴ M

Equilibrium constant  K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq}= \frac{1.395*10^{-4}}{1.090*10^{-2}}

K_{eq} = 0.01279816514  M

K_{eq} = 0.0127 M

ΔG° = - RTinK

ΔG° = -(8.314*298*In(0.0127)

ΔG° = 10817.45913 J

ΔG° = 10817.46 J

5 0
3 years ago
Gaseous methanol (CH4O) reacts with oxygen gas to produce carbon dioxide gas and liquid water. Balanced the equation using the l
NikAS [45]

Answer:

The sum of the coefficients in the balanced equation is 11

Explanation:

A reaction where an organic compound reacts with oxygen to produce carbon dioxide and water is called combustion.

The balance reaction of combustion for methanol is:

2CH₃OH (l) + 3O₂(g) →  2CO₂(g)  +  4H₂O (g)

Coefficients from stoichiometry are 2, 3, 2 and 4

Sum =  2 + 3 + 2 + 4 = 11

4 0
3 years ago
How many moles are in 12 liters of Cl2?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Multiply by the given number of liters: 12

12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Flip the ratio so the liters of chlorine cancel.

12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}

12  * \frac {1 \ mol \ Cl_2}{22.4 }

\frac {12}{22.4 }  \ mol \ Cl_2

0.53571428571 \ mol \ Cl_2

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 0.53<u>5</u>71428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

0.54 \ mol \ Cl_2

12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>

8 0
3 years ago
In ammonium chloride salt (nh4cl) the anion is a single chloride ion, cl. what is the cation of nh4cl
miskamm [114]
NH₄Cl → NH₄⁺ + Cl⁻

NH₄⁺ (the ammonium cation)
5 0
3 years ago
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