Answer: 1 mole ➡️ 6.022×10²³ atoms of si.
X mole ➡️ 2.8×10²⁴ atoms of si.
X = 2.8×10×10²³/6.022×10²³
= 28/6.022
= 4.65 moles.
Explanation:
I believes you would use grams to describe the mass of a tablespoon an you should report that guy
Complete Question
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Answer:
The partial pressure is 
Explanation:
The Partial pressure of 
is mathematically represented as
Where 
is the total pressure of water with a value of 15.5 mm of Hg
is the partial pressure of water with a value 753 mm of Hg
Now substituting values
The molarity of the diluted solution is 0.33 M
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 0. 5 M
Volume of stock solution (V₁) = 100 mL
Volume of diluted solution (V₂) = 100 + 50 = 150 mL
<h3>Molarity of diluted solution (M₂) =? </h3>
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
0.5 × 100 = M₂ × 150
50 = M₂ × 150
Divide both side by 150
M₂ = 50 / 150
<h3>M₂ = 0.33 M</h3>
Therefore, the molarity of the diluted solution is 0.33 M
Learn more: brainly.com/question/24625656
Answer:
pH = 10.38
Explanation:
∴ molar mass C9H13N = 135.21 g/mol
∴ pKb = - log Kb = 4.2
⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]
∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M
mass balance:
⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)
charge balance:
⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water
⇒ [C9H20O3N+] = [OH-].......(2)
(2) in (1):
⇒ [C9H13N] = 1.516 E-3 - [OH-]
replacing in Kb:
⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])
⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0
⇒ [OH-] = 2.3985 E-4 M
∴ pOH = - Log [OH-]
⇒ pOH = 3.62
⇒ pH = 14 - pOH = 14 - 3.62 = 10.38
