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Naddik [55]
3 years ago
9

2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen

Chemistry
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

NCl₃

Explanation:

From the question given above, the following data were obtained:

Mass of nitrogen (N) = 0.77 mg

Mass of chlorine (Cl) = 6.61 mg

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

N = 0.77 mg

Cl = 6.61 mg

Divide by their molar mass

N = 0.77 / 14 = 0.055

Cl = 6.61 / 35.5 = 0.186

Divide by the smallest

N = 0.055 / 0.055 = 1

Cl = 0.186 /0.055 = 3

Therefore, the empirical formula of the compound is NCl₃

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Consider the following reaction at 25 °C: 4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s) An equilibrium mixture contains 1.0 mol Fe, 1.0 × 10–3 mol
tino4ka555 [31]

Answer:

Kc = Kc = 8.0 * 10^9

Kp = 5.5 *10^5

Explanation:

Step 1: Data given

Temperature = 25.0 °C

Number of moles Fe = 1.0 moles

Number of moles O2 = 1.0 * 10^-3 moles

Number of moles Fe2O3 = 2.0 moles

Volume = 2.0 L

Step 2: The balanced equation

4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)

Step 3: Calculate molarity

Molarity = moles / volume

[Fe] = 1.0 moles / 2.0 L

[Fe] = 0.5 M

[O2] = 0.001 moles / 2.0 L

[O2] = 0.0005 M

[Fe2O3] = 2.0 moles / 2.0 L

[Fe2O3] = 1.0 M

Step 4: Calculate Kc

Kc =1/ [O2]³

Kc = 1/0,.000000000125

Kc = 8.0 * 10^9

Step 5: Calculate Kp

Kp = Kc*(R*T)^Δn

⇒with Kc = 8.0*10^9

⇒with R = 0.08206 L*atm /mol*K

⇒with T = 298 K

⇒with Δn = -3

Kp = 8.10^9 *(0.08206 * 298)^-3

Kp = 5.5 *10^5

4 0
3 years ago
If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 4.2 mol of NO₂ were collected, then what is the p
jonny [76]

Answer:

Percent yield = 21%

Explanation:

Find:

Percent yield

Computation:

1 mol O₂ produces 2 mol NO₂

So,

10 mol O₂ produces 20 mol NO₂

Percent yield = [Actual yield / Theoretical yield]100

Percent yield = [4.2 / 20]100

Percent yield = 21%

5 0
3 years ago
A chemist prepares a solution of iron chloride by measuring out of into a volumetric flask and filling to the mark with distille
myrzilka [38]

Complete Question:

A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

Answer:

[Fe+] = 0.0156 M

[Cl-] = 0.0316 M

Explanation:

The molar mass of iron chloride is 126.75 g/mol, thus, the number of moles presented in 0.10 g of it is:

n = mass/molar mass

n = 0.10/126.75

n = 7.89x10⁻⁴ mol

In a solution, it will dissociate to form:

FeCl2 -> Fe+  + 2Cl-

So, the stoichiometry is 1:1:2, and the number of moles of the ions formed are:

nFe+ = 7.89x10⁻⁴ mol

nCl- = 2*7.89x10⁻⁴  = 1.58x10⁻³ mol

The molarity is the number of moles divided by the solution volume, in L (50.0 mL = 0.05 L):

[Fe+] = 7.89x10⁻⁴/0.05 = 0.0156 M

[Cl-] = 1.58x10⁻³/0.05 = 0.0316 M

5 0
3 years ago
Please help thank you
EleoNora [17]

Answer:

f. same number of protons

4 0
3 years ago
Let A be the last two digits of your 8-digit student ID. Example: for 20245347, A = 47 Radio waves, from your favorite radio sta
Shtirlitz [24]

Answer:

2.22 m

Explanation:

Step 1:

Data obtained from the question:

Frequency = (A + 88.3) MHz

We assume that the student ID is 20245347 as given in the question.

Therefore, A = 47 (last two digit of the 8-digit student ID)

Frequency = (47 + 88.3) MHz

Frequency = 135.3 MHz = 135.3x10^6 Hz

Wavelength =?

Recall:

Velocity of electromagnetic wave is 3x10^8 m/s2

Step 2:

Determination of the wavelength of the radio wave. This is illustrated below:

Velocity = wavelength x frequency

Wavelength = Velocity /frequency

Wavelength = 3x10^8 / 135.3x10^6

Wavelength = 2.22 m

5 0
3 years ago
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