In response of what like what’s the full clear question
It's the number of Protons of that atom..
The given question is incomplete. The complete question is as follows.
A certain liquid has a normal boiling point of 
and a boiling point elevation constant 
. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at 
. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.
Explanation:
As per the colligative property, the elevation in boiling point will be as follows.
T = boiling point of the solution =
= boiling point of the pure solvent =
= elevation of boiling constant = 
We will calculate the molality as follows.
molality = 
i = vant hoff's factor
As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.
Putting the given values into the above formula as follows.
m = 100 g
Therefore, we can conclude that 100 g of NaCl was dissolved.
Answer:
Explanation:
Si tomamos en cuenta el peso molecular del agua, que es equivalente a:
1 Átomo de H₂O
O = 16 gr/mol
H = 1 gr/mol
H₂O = 18 gr/mol
Teóricamente sabemos que en 1 mol de H2O habrá 18 gr.
Para obtener los moles presentes en 1 mg de H₂O, (como 1 gr = 1000 mg), decimos:
1 mol H2O ………………………….. 18000 mg
X …………………………… 1 mg
X = 1 / 18000 = 5,56 X 10⁻⁵ moles de H20
Y para obtener la cantidad de moléculas presentes, de acuerdo a los moles, multiplicamos por el número de Avogadro (6,023 X 10²³ moléculas /mol)
Moléculas de H₂O = 5,56x 10⁻⁵ mol x 6,023 x 10²³
Moléculas de H₂O = 3,34488 x10¹⁹ moléculas de H₂O
En el copo de nieve habrá 3,34488 x 10¹⁹ moléculas de H₂O.
Espero que te sirva =)
