This is a question on conservation of energy. That is,
mgh + KE1 = KE2
mgh +1/2mv1^2 = 1/2mv2^2
gh + 1/2v1^2 = 1/2v2^2
Where, h = 0.2 m, v1 =3.04 m/s
Therefore,
v2 = Sqrt [2(gh+1/2v1^2)] = Sqrt [2(9.81*0.2 + 1/2*3.04^2)] = 7.26 m/s
Now, Volumetric flow rate, V/time, t = Surface area, A*velocity, v
Where,
V = Av = πD^2/4*3.04 = π*(2.51/100)^2*1/4*3.04 = 1.504*10^-3 m^3/s
At 0.2 m below,
V = 1.504*10^-3 m^3/s = A*7.26
A = (1.504*10^-3)/7.26 = 2.072*10^-4 m^2
But, A = πr^2
Then,
r = Sqrt (A/π) = Sqrt (2.072*10^-4/π) = 0.121*10^-3 m
Diameter = 2r = 0.0162 m = 1.62 cm
The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.
Answer: Capacitor
Explanation: A capacitor stores energy as charge in an electrical field between two conducting plates called electrodes which allows the flow of electrons between them.
Answer:
if gossipy egg overriding successors spatial
Answer:
The speed when se reaches the top of the incline is 0.28 m/s
Explanation:
The work done is equal to the change of kinetic energy, then:
Wg + Wf + Wn = ΔEk
Where
Wg = work done by gravity
Wf = work done by force
Wn = work done by normal force
Where
m = 8.5 kg
g = 9.8 m/s²
d = 39.93 m
F = 37.4 N
vf = 2 m/s
Replacing:
