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2 years ago

Time dilation means that

1 answer:

5 0

The answer is D. time really does pass more slowly in a rest frame of reference relative to a frame of reference that is moving

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Suppose you are standing on a scale in an elevator that is accelerating upward. Will the scale read your weight as larger for sm

Marta_Voda [28]

Answer:

following are the solution to this question:

Explanation:

When I stand at such a scale in an elevated that's already rising upwards, its scale would appear to also be 0 because of free fall and would often reveal that weight whenever the lift is stable.

In this, the free fall is also known as the object, that is influenced exclusively by gravity, and an object operating only through the influence of gravity is said to be in a free-fall state.

7 0

3 years ago

An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. Determine its age assu

never [62]

Answer:

The age of living tree is 11104 years.

Explanation:

Given that,

Mass of pure carbon = 100 g

Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

We need to calculate the decay rate

$R=\dfrac{-dN}{dt}=\lambda N=\dfrac{0.693}{t_{\frac{1}{2}}}N$ ....(I)

Where, N = number of radio active atoms

$t_{\frac{1}{2}}$ =half life

We need to calculate the number of radio active atoms

For $N_{12_{c}}$

$N_{12_{c}}=\dfrac{N_{A}}{M}$

Where, $N_{A}$ =Avogadro number

$N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}$

$N_{12_{c}}=5.02\times10^{22}\ nuclie/g$

For $N_{c_{14}}$

$N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}$

$N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}$

$N_{c_{14}}=6.526\times10^{10}\ nuclei/g$

Put the value in the equation (I)

$R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}$

$R=15.0650\ decay/min g$

100 g carbon will decay with rate

$R=100\times15.0650=1507\ decay/min$

We need to calculate the total half lives

$(\dfrac{1}{2})^{n}=\dfrac{390}{1507}$

$2^n=\dfrac{1507}{390}$

$2^n=3.86$

$n ln 2=ln 3.86$

$n=\dfrac{ln 3.86}{ln 2}$

$n =1.948$

We need to calculate the age of living tree

Using formula of age

$t=n\times t_{\frac{1}{2}}$

$t=1.948\times5700$

$t=11103.6 =11104\ years$

Hence, The age of living tree is 11104 years.

5 0

3 years ago

A 65 kg student sits 3 m away from a 70 kg student. What is the magnitude of the gravitational force between the two students?

LiRa [457]

Answer:

$F=3.37\times 10^{-8}\ N$

Explanation:

Given that,

Mass of student 1, m₁ = 65 kg

Mass of student 2, m₂ = 70 kg

The distance between the students, d = 3 m

We need to find the magnitude of the gravitational force between the two students. The formula for the magnitude of the gravitational force between two masses is given by :

$F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{65\times 70}{(3)^2}\\F=3.37\times 10^{-8}\ N$

So, the gravitational force between the two students is $3.37\times 10^{-8}\ N$ .

3 0

2 years ago

The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were obser

ELEN [110]

Answer:

a) v² = G M R³, b) T = 2π / $\sqrt{GMR}$ , c) $m \sqrt{GMR^5 }$

Explanation:

a) The kinetic energy is

K = ½ m v²

to find the velocity let's use Newton's second law

F = m a

acceleration is centripetal

a = v² / R

force is the universal force of attraction

F = G m M / r²

we substitute

G m M R² = m v² R

v² = G M R³

the kinetic energy is

K = ½ m G M R³

b) angular and linear velocity are related

v = w R

w = v / R

w = $\frac{\sqrt{GMR^3 }}{R}$

w = $\sqrt{GMR}$

the angular velocity is related to the period

w = 2π / T

T = 2π / w

we substitute

T = 2π / $\sqrt{GMR}$

c) the angular moeomto is

L = m v r

L = m RA G M R³ R

L = $m \sqrt{GMR^5 }$

4 0

3 years ago

A Carnot heat engine has an efficiency of 0.200. If it operates between a deep lake with a constant temperature of 293.0 K and a

Dimas [21]

Answer:

366 K

Explanation:

T₀ = Constant Temperature of deep lake = 293.0 K

T = Temperature of hot reservoir connected to carnot engine = ?

η = Efficiency of Carnot engine during the operation

Efficiency of Carnot engine is given as

$\eta = 1-\frac{T_{o}}{T}$

Inserting the values

$0.200 = 1-\frac{293.0}{T}$

T = 366 K

3 0

3 years ago