Answer: 386.0 g/mol
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
where,
= relative lowering in vapor pressure
i = Van'T Hoff factor = 1 (for non electrolytes)
= mole fraction of solute =
Given : 21.47 g of compound X is present in 233.8 g of diethyl ether
moles of solute (X) =
moles of solvent (diethyl ether) =
= mole fraction of solute =
The molecular weight of this compound is 386.0 g/mol
Outside, because there is more space for it to go, and there is nothing stopping the water from going straight up into the sky.
Answer:
2C2H6 + 7O2 → 4CO2 + 6H2O
Explanation:
First off you find them by balancing the equation ( equal amounts of elements on both sides) So add a two infront of the C2H6. Now you have 4 Carbons and 12 Hydrogens on the left aswell as 2 oxygens.
Now go to the right side and put a 4 infront of CO2 and a 6 infront of H2O. You now have 4 carbons 12 hydrogens and 14 oxygens on the right side.
Finally go back to the let side and place a 7 infront to make the left have 14 oxygens just like in the right. A trick to use is to save the coefficients with only one element till the end so you can do less work in the long run.
But i hope this helped its balanced and down to the smallest whole numbers possible most teachers want whole numbers as the coefficient.
These are tricky at first but once you practice a bit you will be a pro.
Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Explanation :
The given half reaction are :
1st half reaction :
The reduction potential of this reaction = +0.80 V
2nd half reaction :
The reduction potential of this reaction = -0.74 V
From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.
Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.
The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.
Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.