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3 years ago

9

A saturated solution of lead(ii) fluoride, pbf2, was prepared by dissolving solid pbf2 in water. the concentration of pb2+ ion i

n the solution was found to be 2.08×10−3 m. calculate ksp for pbf2

1 answer:

katrin [286]3 years ago

8 0

Equation :

PbF2 ------> Pb2+ + 2F-

Solubility product is given as:

Ksp = [Pb2+][F-]^2

let x = [Pb2+]

Ksp = x(2x)^2 = 4(x)^3 = 4(2.08*10^-3)^3

Ksp = 3.60*10^-8

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<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

By Stoichiometry of the reaction:

When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ

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