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3 years ago

A compound has an empirical formula of CH2 and a molar mass of 70.15. What is its molecular formula?

Chemistry

1 answer:

lina2011 [118]3 years ago

7 0

<h3>Answer:</h3>

Cyclopentane (C5H10)

<h3>Explanation:</h3>

The molar mass of CH2 is about 14.3, Since empirical is a ratio just divide the given molar mass by the molar mass of the empirical. 70.15/14.3=5 So now multiple everything by 5 in the empirical equation.

So, a compound that has an empirical formula of CH2 and a molar mass of 70.15 will have molecular formula of" C5H10".

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3 years ago

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3 years ago

A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L

NeTakaya

Answer:

$\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}$

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

$P_1V_1=P_2V_2$

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

$25.0 \ L * 2.05 \ atm = P_2V_2$

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$25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L$

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

$\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}$