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3 years ago

A compound has an empirical formula of CH2 and a molar mass of 70.15. What is its molecular formula?

Chemistry

1 answer:

lina2011 [118]3 years ago

7 0

<h3>Answer:</h3>

Cyclopentane (C5H10)

<h3>Explanation:</h3>

The molar mass of CH2 is about 14.3, Since empirical is a ratio just divide the given molar mass by the molar mass of the empirical. 70.15/14.3=5 So now multiple everything by 5 in the empirical equation.

So, a compound that has an empirical formula of CH2 and a molar mass of 70.15 will have molecular formula of" C5H10".

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500 cc of 2N Na2CO3 are mixed with 400 cc of 3N H2SO4 and volume was diluted to one litre. Will the resulting solutiomacidic,bas

tester [92]

Answer:

Given info : 500 cc of 2N Na2CO3 are mixed with 400 cc of 3N H2SO4 and volume was diluted to one litre. To find : will the resulting solution is acidic , basic or neutral ? Calculate the molarity of the dilute solution. solution : no of moles of Na2CO3 = normality/n %3D - factor x volume 2/2 x 500/1000 = 0.5 mol %D no of moles of H2SO4 = 3/2 x 400/100O = 0.6 mol %3D We see, Na2CO3 + H2S04 => Na2S04 + CO2 + H2O Here one mol of Na2C03 reacts with one mole of H2SO4. So, 0.5 mol of Na2CO3 reacts with 0.5 mol of H2SO4. so, remaining 0.1 mol of H2SO4 makes solution acidic. Now molarity of solution = remaining no of moles of H2SO4/volume of solution= 0.1/1 = %3D 0.1M

4 0

3 years ago

In the laboratory a student combines 47.8 mL of a 0.321 M aluminum nitrate solution with 21.8 mL of a 0.366 M aluminum iodide so

alex41 [277]

Answer: The final concentration of aluminum cation is 0.335 M.

Explanation:

Given: $V_{1}$ = 47.8 mL (1 mL = 0.001 L) = 0.0478 L

$M_{1}$ = 0.321 M, $V_{2}$ = 21.8 mL = 0.0218 L, $M_{2}$ = 0.366 M

As concentration of a substance is the moles of solute divided by volume of solution.

Hence, concentration of aluminum cation is calculated as follows.

$[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}$

Substitute the values into above formula as follows.

$[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M$

Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.

4 0

3 years ago

When an equation is used to calculate the amount of product that will form during a reaction, then the value obtained is called

bekas [8.4K]

This would be the theoretical yield. This is the amount of product that should be obtained in the end of a reaction, given that none of the reactants are wasted in the creation of the product. This is unlikely to be exactly obtained, however, due to waste products being formed in the process.

6 0

3 years ago

Read 2 more answers

1. The maximum recommended amount of citric acid (H3C6H5O7; the 3 hydrogens listed first are the acidic hydrogens – the only hyd

Lisa [10]

The density has been given as the mass of the substance per volume of the solution. The mass of citric acid in the bottle has been 1.22 grams.

<h3>What is percent mass?</h3>

Percent mass can be given as the mass of substance in the total mass of the solution.

The volume of the face serum has been 250 mL, and the density is 0.979 g/mL.

The mass of face serum in the bottle has been:

$\rm Density=\dfrac{Mass}{Volume}\\ 0.979\;g/mL=\dfrac{Mass}{250\;mL}\\ Mass=244.75\;g$

The total mass of face serum has been 244.75 grams.

The percent mass of citric acid in face serum is 0.5%. This states the presence of 0.5-gram citric acids in 100 grams sample.

The mass of citric acid in the face serum sample is given as:

$\rm 100\;gram\;sample=0.5\;g\;H_3C_6H_5O_7\\\\244.75\;grams\;sample=\dfrac{0.5}{100}\;\times\;244.75\;grams\; H_3C_6H_5O_7\\\\244.75\;grams\;sample=1.22\;grams\;H_3C_6H_5O_7$

The mass of citric acid present in 250 mL serum sample has been 1.22 grams.

Learn more about percent mass, here:

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2 years ago

A compound is 53.31% c, 11.18% h, and 35.51% o by mass. what is its empirical formula?

Alexus [3.1K]

<span>Your final answer would be C4H10O2, which equals 90amu</span>

3 0

3 years ago