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Natali [406]
3 years ago
11

Calculate the average reaction rate of Cl2 consumed using the following information. H2 + Cl2 yields 2 HCl A table with three co

lumns and 3 rows. The first column is titled Time. The second is titled the concentration of H subscript two (molar). The third column is titled the concentration of Cl subscript two (molar). The first row shows 0.00 under time, 0.0505 under H subscript two and 0.0875 under Cl subscript two. The second row shows 10.0 under Time, 0.0255 under H subscript two and 0.0625 under Cl subscript two. 6.81 × 10-1 mol/(L × s) 5.82 × 10-2 mol/(L × s) 7.50 × 10-2 mol/(L × s) 2.50 × 10-3 mol/(L × s)
Chemistry
1 answer:
klemol [59]3 years ago
5 0
Answer : Option D) 2.50 X 10^{-3} Mol/(L s)

Explanation: While calculating the average reaction rate for the given reaction in terms of Cl;

H_{2} + Cl_{2}  ----\ \textgreater \  2HCl.

using the rate equation which is;

\frac{-1}{1}\frac{delta [Cl]}{delta t} = 

\frac{- 0.0875 - 0.0625}{10s - 0s} = 2.50 X 10^{-3} Mol/(L s)
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On the periodic table, calcium is in group 2. What is true about calcium?
Ray Of Light [21]

Answer:

Explanation:

Calcium is all around us. The average human contains approximately 1kg of calcium, of which 99% is stored in our bones. It is the 5th most abundant element in the earth's crust, occurring widely as calcium carbonate which is more commonly known as limestone. It is also the fifth most abundant dissolved ion in seawater.

6 0
3 years ago
What is the pH range for an acid? <br> 0-7<br> 7-14<br> 7<br> 0
olga nikolaevna [1]
<h3>Answer: Choice A)  0-7</h3>

Explanation:

If the pH is between 0 and 7, then we have an acid.

If the pH is between 7 and 14, then we have an alkaline base.

If pH = 7, then it's neutral.

7 0
2 years ago
Read 2 more answers
3. Given 20g of Barium Hydroxide, how many grams of
anastassius [24]

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =\frac{20}{171.34}

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

6 0
2 years ago
2Al + 3Br2 --&gt; 2AlBr3
vlada-n [284]
A) The limiting reactant is Al
b) Br2 is the excess reactant
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4 0
2 years ago
How many grams of CuF2 are needed to make a 2.8 M solution
11111nata11111 [884]
Molarity is given as,

                              Molarity  =  Moles / Volume of Solution  ----- (1)

Also, Moles is given as,

                              Moles  =  Mass / M.mass

Substituting value of moles in eq. 1,

                              Molarity  =  Mass / M.mass × Volume

Solving for Mass,

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Data Given;

                  Molarity  =  2.8 mol.L⁻¹

                  M.mass  =  101.5 g.mol⁻¹

                  Volume  =  1 L (I have assumed it because it is not given)

Putting values in eq. 2,

                              Mass  =  2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

                              Mass  =  284.2 g of CuF₂
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3 years ago
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