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Natali [406]
3 years ago
11

Calculate the average reaction rate of Cl2 consumed using the following information. H2 + Cl2 yields 2 HCl A table with three co

lumns and 3 rows. The first column is titled Time. The second is titled the concentration of H subscript two (molar). The third column is titled the concentration of Cl subscript two (molar). The first row shows 0.00 under time, 0.0505 under H subscript two and 0.0875 under Cl subscript two. The second row shows 10.0 under Time, 0.0255 under H subscript two and 0.0625 under Cl subscript two. 6.81 × 10-1 mol/(L × s) 5.82 × 10-2 mol/(L × s) 7.50 × 10-2 mol/(L × s) 2.50 × 10-3 mol/(L × s)
Chemistry
1 answer:
klemol [59]3 years ago
5 0
Answer : Option D) 2.50 X 10^{-3} Mol/(L s)

Explanation: While calculating the average reaction rate for the given reaction in terms of Cl;

H_{2} + Cl_{2}  ----\ \textgreater \  2HCl.

using the rate equation which is;

\frac{-1}{1}\frac{delta [Cl]}{delta t} = 

\frac{- 0.0875 - 0.0625}{10s - 0s} = 2.50 X 10^{-3} Mol/(L s)
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grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
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3 years ago
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2.0 atoms of K and 1.0 atom of S are needed to form a molecule of potassium sulfide.

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<u><em>So, 2.0 atoms of K and 1.0 atom of S are needed to form a molecule of potassium sulfide.</em></u>

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What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
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Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

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Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
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=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

8 0
2 years ago
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