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3 years ago

Type one to two paragraphs describing the changes in potential and kinetic energy of the cart.

Chemistry

2 answers:

Deffense [45]3 years ago

8 0

Answer:

potential energy is energy that is stored in an object. Can also transfer into others forms of energy. Kinetic energy is energy an object has become of its motion.

Umnica [9.8K]3 years ago

3 0

Answer:

When the cart started at the top of the hill it was full Potential Energy. As the cart started to go down the hill it was gaining speed turning it into (PE/KE) Kinetic Energy. That transition occurred because Kinetic Energy only happens when something gains speed. As the cart hit the valley. (on poster) It was still full of Kinetic Energy. As the cart started moving up the last hill it was transitioning from Kinetic Energy, to Potential Energy, (KE, PE). Which then led to the cart coming to a stop on the second hill as Potential Energy. (PE)

Please mark me brainliest.

Hope I helped.

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Read 2 more answers

Study this chemical reaction: (aq)(s)(s)(aq) Then, write balanced half-reactions describing the oxidation and reduction that hap

disa [49]

The question is incomplete, complete question is:

Study this chemical reaction:

$FeSO_4 (aq) + Zn (s)\rightarrow Fe (s) + ZnSO_4 (aq)$

Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Oxidation:

Reduction:

Answer:

Oxidation taking place in given reaction :

$Zn(s)\rightarrow Zn^{2+}+2e^-$

Reduction taking place in given reaction;

$Fe^{2+}(aq)+2e^-\rightarrow Fe(s)$

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

$FeSO_4 (aq) + Zn (s) \rightarrow Fe (s) + ZnSO_4 (aq)$

In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.

Oxidation :

$Zn(s)\rightarrow Zn^{2+}+2e^-$

Reduction ;

$Fe^{2+}(aq)+2e^-\rightarrow Fe(s)$

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