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3 years ago

Find the co valance of c in C2S2

Chemistry

1 answer:

Effectus [21]3 years ago

5 0

Answer:

A better term than

covalency

might be

molecularity

. Molecular species TEND to have reduced melting points and boiling points with respect to non-molecular species. Non molecular species, which include sodium chloride, and graphite, and diamond, thus have much HIGHER melting points than methane or ethane, or water, which are composed of discrete molecules.

Explanation:

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3 years ago

Hot asphalt poured onto flat ground cools to form a solid road surface. Chemical or physical change

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<h2>Answer:</h2>

This is a physical change.

<h3>Explanation:</h3>

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3 years ago

A sample of an unknown gas effuses in 14.4 min. An equal volume of H2 in the same apparatus under the same conditions effuses in

Elena-2011 [213]

Answer:- molar mass of the unknown gas is 71.5 gram per mol.

Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

When we compare the effusion rates of two gases then the formula for Graham's law is:

$\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}$

In this formula, V stands for volume and M stands for molar mass

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

$\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}$

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.

Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:

$\frac{14.4}{2.42}=\sqrt{\frac{M_2}{2.02}}$

$5.95=\sqrt{\frac{M_2}{2.02}}$

doing squares to both sides:

$35.4=\frac{M_2}{2.02}$

$M_2=35.4*2.02$

$M_2=71.5$

So, the molar mass of the unknown gas is 71.5 grams per mol.

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3 years ago

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saveliy_v [14]

Answer: Heat

Explanation:

when there is enough air in the balloon that is when the crew would blast the burner into the envelope mouth building the pressure until the balloon inflates until it starts to lift off the ground and as the air builds up the balloon will lift right off the ground

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3 years ago

Find the co valance of c in C2S2 ​

Find the co valance of c in C2S2