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UkoKoshka [18]
3 years ago
15

5. Evaluate the function f (x) = 4 • 7x for x = -1 and x = 2. Show your work.

Mathematics
1 answer:
mylen [45]3 years ago
5 0
F(-1)= 4*7(-1) = 4*-7 = -28

F(2)= 4*7(2) = 4*14 = 56
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Suppose that a department contains 9 men and 15 women. How many different committees of 6 members are possible if the committee
Drupady [299]

Answer:  The required number of different possible committees is 81172.

Step-by-step explanation:    Given that a department contains 9 men and 15 women.

We are to find the number of different committees of 6 members that are possible if the committee must have strictly more women than men.

Since we need committees of 6 members, so the possible combinations are

(4 women, 2 men), (5 women, 1 men) and (6 women).

Therefore, the number of different committees of 6 members is given by

n\\\\\\=^{15}C_4\times ^9C_2+^{15}C_5\times ^9C_1+^{15}C_6\\\\\\=\dfrac{15!}{4!(15-4)!}\times \dfrac{9!}{2!(9-2)!}+\dfrac{15!}{5!(15-5)!}\times \dfrac{9!}{1!(9-1)!}+\dfrac{15!}{6!(15-6)!}\\\\\\\\=\dfrac{15\times14\times13\times12\times11!}{4\times3\times2\times1\times11!}\times\dfrac{9\times8\times7!}{2\times1\times7!}+\dfrac{15\times14\times13\times12\times11\times10!}{5\times4\times3\times2\times1\times10!}\times\dfrac{9\times8!}{1\times8!}+\dfrac{15\times14\times13\times12\times11\times10\times9!}{6\times5\times4\times3\times2\times1\times9!}\\\\\\=1365\times36+3003\times9+5005\\\\=49140+27027+5005\\\\=81172.

Thus, the required number of different possible committees of 6 members is 81172.

8 0
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AveGali [126]

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Step-by-step explanation:

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Which rules give a repeating pattern that has a 7 as the 15th number? Select all that apply.
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Pls answer<br><br> 5x-7y=58<br> y=-x+2
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Answer:

x = 6

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Step-by-step explanation:

Plug y into the first equation.

5x - 7(-x+2) = 58

Then, solve for x.

Plug in x back to any one of the equations to find y.

8 0
3 years ago
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First to answer will be the brainliest I need the answer ASAP
tatuchka [14]
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