The relative pressure at this state is determined as 0.455.
<h3>Initial pressure of the ideal gas </h3>
The pressure of the ideal gas given rise to the relative pressure is calculated as follows;
R.P = P2/P1
P2 = P1(R.P)
P2 = 200 kPa x (3.482)
P2 = 696.4 kPa
<h3>New relative pressure</h3>
R.P = (P3)/(P2)
R.P = (320)/(696.4)
R.P = 0.455
Thus, the relative pressure at this state is determined as 0.455.
Learn more about relative pressure here: brainly.com/question/15584931
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Answer:
the only one of these materials that allows studying processes of a very long period of time is Uranium 238
Explanation:
In a radioactive material, half of the atoms decay each life period, in carbon 14 this period T = 5730 years, so for a time of 40,000 years there are 7 life periods, so there are very few atoms left without decomposing .
To study older samples, materials with a longer life period are needed, let's show the visa time
²³⁸U T= 4.5 10¹⁰ years
⁹¹Rb T = 58 s
¹³¹I T= 8.04 days
⁶⁰Co T= 5.27 years
Therefore, the only one of these materials that allows studying processes of a very long period of time is Uranium 238
To calculate the threshold frequency of the metal we use the formula,
Also,
Here, E is the energy of electron per atom, h is plank constant.
Given, binding energy of electron or for one electron,, here N is the Avogadro constant and its value is , so and plank constant,
Substituting these values in above relation we get,
.
Thus, the threshold frequency of the metal is .
Answer:
44
Explanation:
jk you didnt share the video lol
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