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Olin [163]
3 years ago
5

A ball thrown horizontally at 12.6 m/s from the roof of a building lands 20.0 m from the base of the building

Physics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

1.59 seconds

12.3 meters

but if you are wise you will read the entire answer.

Explanation:

This is a good question -- if not a bit unusual. You should try and understand the details. It will come in handy.

Time

<u>Given</u>

a = 0 This is the critical point. There is no horizontal acceleration.

d = 20 m

v = 12.6 m/s

<u>Formula</u>

d = vi * t + 1/2at^2

<u>Solution</u>

Since the acceleration is 0, the formula reduces to

d = vi * t

20 = 12.6 * t

t = 20 / 12.6

t = 1.59 seconds.

It takes 1.59 seconds to hit the ground

Height of the building

<u>Givens</u>

t = 1.59 sec

vi = 0     Another critical point. The beginning speed vertically is 0

a = 9.8 m/s^2   The acceleration is vertical.

<u>Formula</u>

d = vi*t + 1/2 a t^2

<u>Solution</u>

d = 1/2 a*t^2

d = 1/2 * 9.8 * 1.59^2

d = 12.3 meters.

The two vi's are not to be confused. The horizontal vi is a number other other 0 (in this case 12.6 m/s horizontally)

The other vi is a vertical speed. It is 0.

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The rate constant of a reaction is 7.8 × 10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C? Enter yo
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Answer:

k_2 = 7.815 * 10^-3 s^-1

Explanation:

Given:

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- Gas constant R = 8.314472 KJ / mol . K

Find:

- rate of reaction k_2 @ T_2 = 75 C

Solution:

- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:

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- Evaluate             k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)

- Hence,                k_2 = 7.815 * 10^-3 s^-1

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Answer:

All the observers are correct.

Explanation:

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From their various reference frames, they are all correct.

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This is clearly shown by what observer A noticed. There was a relative motion between the book and the car as she pointed out, making her to be in an inertial reference frame.

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This is shown by observer B as he is able to notice how the force of the car affects the velocity of the book.

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