Pressure is equal to the ratio of thrust to the area in contact. Upthrust is a force exerted by the fluids on an object placed in the fluid . Upthrust acts in upward direction.

4 0

3 years ago

Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. The

AnnyKZ [126]

Answer:

Fy=107.2 N

Explanation:

Conceptual analysis

For a right triangle :

sinβ = y/h formula (1)

cosβ = x/h formula (2)

x: side adjacent to the β angle

y: opposite side of the β angle

h: hypotenuse

Known data

h = T = 153.8 N : rope tension

β= 44.2°with the horizontal (x)

Problem development

We apply the formula (1) to calculate Ty : vertical component of the rope force.

sin44.2° = Ty/153.8 N

Ty = (153.8 N ) *(sen44.2°)= 107.2 N directed down

for equilibrium system

Fy= Ty=107.2 N

Fy=107.2 N upward component of the force acting on the stake

8 0

3 years ago

Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t

Serga [27]

we know that center of mass is given as

r = (m₁ $r_{1x}$ + m₂ $r_{2x}$ )/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ d $r_{1x}$ /dt + m₂ d $r_{2x}$ /dt)/(m₁ + m₂)

v = (m₁ $v_{1x}$ + m₂ $v_{2x}$ )/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ d $v_{1x}$ /dt + m₂ d $v_{2x}$ /dt)/(m₁ + m₂)

a= (m₁ $a_{1x}$ + m₂ $a_{2x}$ )/(m₁ + m₂)

3 0

3 years ago

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