The lower limit that could be used to determine the position of each object along the direction of the velocity is 1.136 x 10⁻³ m.
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Uncertainty in the position of the electron</h3>
The uncertainty in the position of the electron is calculated as follows;
where;
- h is Planck's constant = 6.63 x 10⁻³⁴ Js
- m is mass of electron
- Δv uncertainty in velocity = (0.01 x 10⁻²) x 510 = 0.051 m/s
Thus, the lower limit that could be used to determine the position of each object along the direction of the velocity is 1.136 x 10⁻³ m.
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Answer: initially the packet was ascending up with the balloon.
Taking upward as positive direction;
initial velocity, u = 4.9 m/s
final velocity = v m/s
initial height, h₁ = 245 m
final height, h₂ = 0
a = -9.8 m/s²
time taken = t seconds
s = ut + 0.5at²
⇒ (h₂-h₁) = ut + 0.5at²
⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²
⇒ -245 = 4.9t - 4.9t²
⇒ 4.9t² -4.9t -245 =0
Solving it, we get t = 7.59s
v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s
So velocity is 69.48 m/s downward
Explanation:
Answer:
The result is a vector perpendicular to the xy plane: 23.38 k
Explanation:
The cross product of two vectors r and s is defined only in three-dimensional space and is denoted by r × s. The cross product is defined by the formula:
r × s =║r║·║s║· Sin θ· n
where θ is the angle between r and s in the plane containing them, ‖r‖ and ‖s‖ are the magnitudes of vectors r and s, and n is a unit vector perpendicular to the plane containing a and b in the direction given by the right-hand rule.
So, the result is:
r × s = 4.40 * 7.45 * Sin (134.5°) k = 23.38 k
Answer:
14.17H
Explanation:
Energy stored in an inductor is expressed as;
E = 1/2LI²
L is the inductance of the inductor
I is the current flowing through the inductor
Given
E = 10.2J
I = 1.20
Required
Inductance L
Substitute the given parameters into the formula;
10.2 = 1/2L(1.2)²
10.2 = 1/2*1.44L
10.2 = 0.72L
L = 10.2/0.72
L = 14.17H
Hence the self inductance of the solenoid is 14.17H