Answer:
0.0006091222 m
Explanation:
q = Charge = 42 pC
V = Voltage = 620 V
= Permittivity of free space =
Electric potential is given by (at r = R)
The radius of the drop is 0.0006091222 m
0.5m/s2
acceleration= change in velocity/time taken
= v - u/ t
= 10-5/10
=5/10
= 0.5m/s2
Answer:B
Y is the brightest bulb