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mamaluj [8]
3 years ago
9

What is the acceleration of an object with a mass of

Physics
1 answer:
aev [14]3 years ago
3 0

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                             F = Force = 183 N

                                            m = Mass = 367 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\boxed{a=183 \ N / 367\ kg}

⇒ Resolving

\boxed{ a = 0.49 \ m/s^{2}}

Result:

The aceleration is <u>0,49 meters per second squared (m/s²)</u>

Good Luck!!

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D) It isn't accelerating
This is because if both sides are pushing with the exact same force, than one force is not overpowering the other, therefor the wheelbarrow would not be moving.

6 0
3 years ago
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A wave has a frequency of 12 Hz and a wavelength of 5 m. What is the wave speed?
Feliz [49]

Answer:

The speed of the wave is 15ms .

Explanation:

7 0
2 years ago
A person driving her car at 43 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow
siniylev [52]

Answer:

If she hits the brakes, she will travel 13m before stopping. If she hits the gas, she will travel 28 before the light turns red. She should try to stop

Explanation:

To know how far she will travel before stopping, we need to use a kinematic formula which initial final velocity (Vf), initial velocity (V0), acceleration (a) and distance traveled(x):

V_{f}^{2}=V_{0} ^{2} +2ax

The moment in which she stops is when the final velocity equals zero. In this case, initial velocity is 43km/h=12m/s, and its maximum deceleration is -5.4m/s^2. Plugging in these values and solving for x:

0^2=(12m/s)^2+2(-5.4m/s)x\\x=13m

She will travel 13m before stopping

If she hits the gas, we need another kinematic formula, which relates distance traveled, initial speed, time (t) and acceleration.

x=v_{0}t+0.5a*t^2

If we know her car can accelerate from 43km/h=12m/s to 70km/h=19m/s in 8.1 s, we can know its acceleration:

a=\frac{19m/s-12m/s}{8.1s}=0.86m/s^2

In this case, the time before the light turns red is 2.0s. Plugging in all those values:

x=12m/s*2s+0.5*0.86m/s^2*(2s)^2=28m

If she hits the gas, she will travel 28m before the light turns red. She won't even reach the intersection, so she would try to stop.

5 0
3 years ago
What is the total current for the parallel circuit?​
Anton [14]

Answer:

\huge\boxed{\sf Current = 6\ Ampere}

Explanation:

<u>In a parallel circuit, Total resistance is:</u>

\displaystyle \frac{1}{R_T} =\frac{1}{R_1} +\frac{1}{R_2}

Where R_1 = 6Ω and R_2 = 12Ω

<h3><u>Finding </u>R_T\\<u>:</u></h3>

\displaystyle \frac{1}{R_T} =\frac{1}{6} +\frac{1}{12} \\\\\frac{1}{R_T} =\frac{1 \times 2+1}{12} \\\\\frac{1}{R_T} =\frac{3}{12} \\\\\frac{R_T}{1} = \frac{12}{3} \\\\\boxed{R_T=4 \ Ohm}

<h3><u>Finding current:</u></h3>

<u>We know that:</u>

<h3>V = IR (Ohm's Law)</h3>

V = 24 V, R = 4 Ω (V given, R found)

24 = I(4)

Divide 4 to both sides

6 A = I

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\rule[225]{225}{2}

8 0
2 years ago
Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i
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Answer:

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We must use conservation of linear momentum before and after the collision, p_i=p_f

Before the collision we have:

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where these are the masses are initial velocities of both players.

After the collision we have:

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since they clong together, acting as one body.

This means we have:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Or:

v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Which for our values is:

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7 0
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