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kvv77 [185]
2 years ago
5

Write the balanced net reaction for the following half cells: Sn2+ / Sn Cr2+ / Cr

Chemistry
1 answer:
GuDViN [60]2 years ago
4 0

The balanced net reactiion for the following half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

<h3>What are Half cells ?</h3>

A half cell is one of the two electrodes of an electrochemical cell.

An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.

A salt bridge or direct contact is needed to connect two half cells.

The balanced net reactiion for the given half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

Learn more about Half cell here ;

brainly.com/question/1313684

#SPJ1

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Identify the alkane that contains four carbons.
Thepotemich [5.8K]
Butane is the alkane that have 4 carbons
7 0
3 years ago
Binary compounds of alkali metals and hydrogen react with water to liberate hydrogen gas. The hydrogen gas from the reaction of
DanielleElmas [232]

Answer: The mass of H_{2} liberated is 0.0383 g and the mass of NaH that reacted 0.455 g.

Explanation:

The given data is as follows.

       Volume = 0.501 L,

 Temperature of gas = 35^{o}C = (35 + 273) K = 308 K,

 Total pressure = 760 mm Hg

  Vapor pressure of water at 35^{o}C = 422 mm Hg

  Partial pressure of H_{2} = (760 - 422) mm Hg

                                     = 717.8 mm Hg

The chemical equation is as follows.

       NaH + H_{2}O \rightarrow NaOH + H_{2}

Using ideal gas equation, we will find the moles of hydrogen gas as follows.

             PV = nRT

         n = \frac{PV}{RT}

As we know,

               1 atm = 760 mm Hg

      717.8 mm Hg = 717.8 \times \frac{1 atm}{760 mm Hg}    

                             = 0.944 atm

Putting the given values into the above formula we will calculate the number of moles as follows.

                    n = \frac{PV}{RT}

                       = \frac{0.944 atm \times 0.510 L}{0.08206 Latm/mol K \times 308 K}

                       = 0.0190 moles

Now, we will find the mass of H_{2} as follows.

       Mass = Moles × Molar mass

                 = 0.0190 moles × 2.01588 g/mol

                 = 0.0383 g

Therefore, mass of hydrogen is 0.0383 g.

As the ratio between H_{2} and NaH is 1:1. So, we will calculate the moles of NaH as follows.

             Mass = Moles × Molar mass

                       = 0.0190 moles × 23.99771 g/mol

                       = 0.455 g

Therefore, mass of NaH is 0.455 g.

6 0
2 years ago
What is the ground state electron configuration for Ru2+?
Natali5045456 [20]

Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.

Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.

Now, Ru stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.

One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.

Ground electronic Configuration is as follows:

Ru = s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}4d^{7}

Soft Hand notation: [Kr]4d^{7}5s^{1}

Now, when ruthenium loses two electrons then it becomes Ru^{+2}, thus electron configuration becomes

Soft Hand notation: [Kr]4d^{6}

The ground state electronic configuration of Ruthenium is [Kr]4d^{7}5s^{1} and when it loses two electrons, then electronic configuration becomes [Kr]4d^{6} ( Ru^{+2})





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3 years ago
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<span>3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles</span>
8 0
2 years ago
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A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 203 kPa and the temperature
dybincka [34]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

V2 = P1 V1 / P2

V2 = 153 x 3.00 / 203

<span>V2 = 2.26 L</span>

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2 years ago
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