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Marianna [84]
3 years ago
5

An object has a mass of 20 g and volume of 10 cm. Enter the numerical value for the density of the object in units of g/cmº

Chemistry
1 answer:
Nady [450]3 years ago
6 0

Answer:

density = 2g/cm³

Explanation:

density = mass/volume

mass = 20g

volume = 10cm³

density = 20g/10cm³

density = 2g/cm³

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Answer:

B) Transportation and photosynthesis

C) Cellular respiration and photosynthesis

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Predict the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, S
777dan777 [17]
1) Chemical equation

16Fe(s) + 3S8(s) ---> 8Fe2S3

2) Molar ratios:

16 mol Fe : 3 mole S8 : 8 mol Fe2S3

3) Convert masses in grams to number of moles

number of moles = mass in grams / molar mass

a) iron, Fe

mass = 3.0 g
atomic mass = 55.845 g/mol

=> number of moles of Fe = 3.0g / 55.845 g/mol = 0.0537 mol

b) Sulfur, S8

mass = 2.5 g
molar mass = 8*32.065 g/mol = 256.52 g/mol

=> number of moles of S8 = 2.5g / 256.52 g/mol = 0.009746 mol

4) Limiting reactant

Theoretical ratio                           actual ratio

16 mol Fe / 3 mol S8                 0.0537 mol Fe / 0.009746 mol S8

5.33                                               5.50

So, there is a little bit more Fe than the theoretical needed to react all the S8, which means the S8 is the limiting reactant.

5) Calculate the number of moles of iron (III) produced with 2.5 g (0.009746 moles) of S8

3moles S8 / 8 moles Fe2S3 = 0.009746 moles S8 / x

=> x = 0.009746 * 8 / 3 moles Fe2S3 = 0.026 moles Fe2S3

6) Convert 0.026 moles Fe2S3 into grams

mass in grams = number of moles * molar mass

molar mass of Fe2S3 = 207.9 g/mol

mass = 0.026 mol * 207.9 g/mol = 5.40 g

7) Answer: option D)




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3 years ago
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C. Model. It's a graphical model that displays one or more weather elements. 
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Which of the following examples depict(s) a physical property?
dimaraw [331]

Answer:

D

Explanation:

All explain physical no chemical examples were given

6 0
3 years ago
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Two tons of water is pumped into a tank 15 ft. High in 5 minutes. Determine the power output of the pump. (Note: One ton is equa
Semmy [17]

Answer:

200 lb•ft/s

Explanation:

From the question given above, the following data were obtained:

Force (F) = 2 tons

Time (t) = 5 mins

Height (h) = 15 ft

Power (P) =?

Next, we shall convert 2 tons to pound. This can be obtained as follow:

1 ton = 2000 lb

Therefore,

2 tons = 2 × 2000

2 tons = 4000 lb

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

5 mins = 5 × 60

5 mins = 300 s

Finally, we shall determine the power of the pump. This can be obtained as follow:

Force (F) = 4000 lb

Time (t) = 300 s

Height (h) = 15 ft

Power (P) =?

P = F × h / t

P = 4000 × 15 / 300

P = 60000 / 300

P = 200 lb•ft/s

Thus, the power of the pump is 200 lb•ft/s

5 0
3 years ago
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