K:
m=155g
M=39g/mol
n = 155g / 39g/mol ≈ 3,97mol
KNO₃:
m=122g
M=101g/mol
n = 122g/101g/mol = 1,21mol
2K + 10KNO₃ ⇒ 6K₂O + N₂
2mol : 10mol
3,97mol : 1,21mol
limiting reagent
KNO₃ is limiting reagent
The answer is a because the water we use it comes back again
Answer:
The rate of acceleration is 5.
Explanation:
In order to calculate acceleration we need to divide the force by the mass.
Acceleration = net force/mass
In this case, it would be 20/4. Simplify that and we get 5.
Answer:
for the reaction is 5.55
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.
The given balanced equilibrium reaction is,
At eqm. conc. (0.010) M (0.15) M (0.37) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get :


Thus the
for the reaction is 5.55