1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ad libitum [116K]
3 years ago
15

Find the sum of the first 25 multiples of 10.​

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:

3250

Step-by-step explanation:

First 25 multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55

11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 155

21 + 22 + 23 + 24 + 25 = 115

55 + 155 = 210

210 + 115 = 325

325 x 10 = 3250

Hope this helped!

poizon [28]3 years ago
3 0

Answer:

Step-by-step explanation: So the first 25 multiples of 10 are ,

10,10,10,10 ect, to 25 the sum of all of the numbers is 250 i hope this helped!!!

You might be interested in
There are some oranges in a box. The total weight of these oranges is 4.29 kg. The
-BARSIC- [3]

Answer:

There are 44 oranges in the box

Step-by-step explanation:

4.29 kg = 4290 g

4290g / 97.5 g = 44

3 0
3 years ago
Of 136 people visiting an art gallery, 17 bought paintings. What percent of the visitors bought a painting? Answer for crown :)
8_murik_8 [283]

Answer:

12.5%

Step-by-step explanation:

7 0
3 years ago
1<br> 2<br> 3<br> 4<br> Pls help meee!!!
Rus_ich [418]

Answer:x=2

Step-by-step explanation:

3 0
3 years ago
in a box of chocolates, 1/5 of the chocolates contain nuts. the rest of the chocolates do not contain nuts. write down the ratio
valina [46]

Answer:

The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4

Step-by-step explanation:

The parameters given are;

Proportion of the box of chocolates that contain nuts = 1/5

Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5

Therefore, we have in a box of chocolates with five chocolates;

The number of chocolates that contain nuts = 1

The number of chocolates that do not contain nuts = 4

Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.

4 0
3 years ago
If x^2-x-6 and x^2+3x-18 hacpve a common factor (x-a) then find the value of a.​
DedPeter [7]

Answer:

a = 3

Step-by-step explanation:

Factor both expressions

x² - x - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are - 3 and + 2 , since

- 3 × 2 = - 6 and - 3 + 2 = - 1 , thus

x² - x - 6 = (x - 3)(x + 2)

-----------------------------------

x² + 3x - 18

consider factors of constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3 , since

6 × - 3 = - 18 and 6 - 3 = + 3 , thus

x² + 3x - 18 = (x + 6)(x - 3)

Both expressions have a common factor of (x - 3)

Compare with (x - a ), then a = 3

3 0
2 years ago
Read 2 more answers
Other questions:
  • If dy/dx equals cosine squared of the quantity pi times y over 2 and y = 0.5 when x = 0, then find the value of x when y = 2.5.
    7·1 answer
  • Plz help me plz someone I need he help plz anyone I need help plz help me plz I swear I need the help plz help me
    12·1 answer
  • A board game that normally costs $30 is on sale for 25 percent off. What is the sale price for the game?
    11·2 answers
  • Which is the graph of y – 3 = (x + 6)?
    12·2 answers
  • What is the vertex of the graph of y = −4(x + 2)2 + 5?<br> (2, 5)<br> (−2, 5)<br> (5, −2)<br> (5, 2)
    15·2 answers
  • g When you take all possible samples of a given n size, calculate a statistic on all these possible samples, and then put all th
    8·1 answer
  • 1 Write the slope-intercept form of the equation of the line. -​
    14·1 answer
  • 10 Students were surveyed.
    5·1 answer
  • 2-2 this is a freebie for points guys
    12·2 answers
  • The Apollo space program lasted from 1967 until 1972 and included 13 missions.The missions lasted from as little as Z hours to a
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!