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Komok [63]
3 years ago
10

I have this sheet and I don’t understand any of it at all

Physics
1 answer:
katen-ka-za [31]3 years ago
3 0

I know this probably is not what you are looking for, but this is what I would suggest.

Write down on the side what values they are giving you and the corresponding variable used for that value.

Like for the first question, they give you mass is 3000kg.

On the side write

m = 3000kg

m is the variable used for mass

Then list any other variables they give you in the question and then what you are trying to look for.

a = 2m/s^2

F = ?

a is the variable for acceleration and F is the variable for force.

So now you have:

m = 3000kg

a = 2m/s^2

F = ?

You have a and m, and you are looking for F (force), you know that because it asks "with what force".

Also note, that you have to know what the variable is based on the units and you likely have some type of formula sheet with all of them listed.

You can use the variables and what is unknown to match it to a formula that will solve for the unknown variables. Also note, that it might not always be simply a=b+c, you may know what "a" and "b" are, but they may ask for c so you will have to rearrange the formula with some simple algebra.

This question however is simple. You can see you are going to use the formula

F=ma.

So now just substitute in your variables to solve for F.

(3000kg)(2m/s^2) = 6000N

<u>Make sure to write the units</u> which are probably on your formula sheet as well. Force is measured in Newtons, so you use the unit N.

Also note, if they gave you mass in grams (another unit), you cannot use that in the formula (your formula sheet would tell you the unit it must be in), so you would have to convert it to kg.

Hope this helps as a starting point. I don't intend to do your homework for you, but explain a process you can use to help you do it on your own.

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You can only score 1 point when shooting a free throw. Group of answer choices True False
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2 points

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2 years ago
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Three point charges are placed on the x−y plane: a + 50.0-nC charge at the origin, a −50.0-nC charge on the x axis at 10.0 cm, a
butalik [34]

Answer:

(a) F = 0.00322i - 0.00793j with magnitude |F| = 0.00856N

(b) E = -42846.7 N/C

Explanation:

The diagram attached below explains some parameters.

Parameters given:

Charge Q1 = +50 nC at point (0, 0)

Charge Q2 = -50 nC at point (0.1, 0)

Charge Q3 = +150 nC at point (0.1, 0.08)

* The distances are in meters.

(a) The total electric force on the charge Q3 due to Q1 and Q2 is the vector sum of the forces due to Q1 and Q2. Mathematically,

F = F1 + F2

FORCE DUE TO Q1 i.e. F(Q1, Q3)

We have to find the x and y components.

From the diagram, we can find θ using SOHCAHTOA:

θ = tan⁻¹ (0.08/0.1)

θ = 38.66⁰

The distance between Q1 and Q3 can be found using Pythagoras theorem:

x² = 0.08² + 0.1²

x = 0.128 m

F1 = Fx(Q1, Q3)i + Fy(Q1, Q3)j

F1 = iF(Q1, Q3)cosθ + jF(Q1, Q3)sinθ

F(Q1, Q3) = (k * Q1 * Q3) / r²

k = Coulombs constant

F(Q1, Q3) = (9 * 10⁹ * 50 * 10⁻⁹ * 150 * 10⁻⁹) /(0.128)²

F(Q1, Q3) = 0.00412N

F1 = i0.00412 * cos38.66 + j0. 00412 * sin38.66

F1 = 0.00322i + 0.00257j N

FORCE DUE TO Q2 i.e. F(Q2, Q3)

We have to find the x and y components.

F2 = Fx(Q2, Q3)i + Fy(Q2, Q3)j

F2 = iF(Q2, Q3)cos90 + jF(Q2, Q3)cos0

F(Q2, Q3) = (k * Q2 * Q3) / r²

F(Q2, Q3) = (9 * 10⁹ * -50 * 10⁻⁹ * 150 * 10⁻⁹) /(0.08)²

F(Q2, Q3) = -0.0105N

F2 = -i0.0105 * cos90 - j0.0105 * cos0

F2 = - 0.0105j N

Hence, the total force will be

F = F1 + F2

F = 0.00322i + 0.00257j - 0.0105j

F = 0.00322i - 0.00793j N

The magnitude of this force is:

|F| = √(0.00322² + (-0.00793²)

|F| = 0.00856N

(b) The electric field at charge Q3 is the sum of the electric fields due to Q1 and Q2:

E = E1 + E2

E1, electric field due to Q1 = kQ1/r²

E1 = (9 * 10⁹ * 50 * 10⁻⁹) / (0.128²)

E1 = 27465.8 N/C

E2, electric field due to Q2 = (9 * 10⁹ * -50 * 10⁻⁹) / (0.08²)

E1 = -70312.5N/C

The total electric field:

E = E1 + E2

E = 27465.8 - 70312.5

E = -42846.7 N/C

3 0
3 years ago
87) Determine the equivalent resistances for the following circuits.
stepladder [879]

Answer:

15    and  11 ohms

Explanation:

First one =   For the parallel resistors 1 / (1/6 + 1/6 + 1/6) =   1/ (3/6 ) = 6/3 = 2 ohms   then add the 3 and the 10  = 15 ohms

second one    for the parallel portion   equiv =    (10+2)*24 / ( (10+2 + 24) = 8

  then add the  3 in series = 11 ohms

8 0
2 years ago
What are the major features of the human eye and to what are they analogous in a camera?
adelina 88 [10]

Answer:

The human major features with the analogous of camera are mentioned.

Explanation:

There are the following major features of human eye which are analogue with the camera:

  • Camera will have shutters which controls light entering into it, human eye consists of Diaphragm which also functions same.
  •  Both gives Real & inverted images.
  •  In camera film records image, in eye image is focused on retina and it is converted into electrical impulses.
  •  Pupil and iris acts as aperture of camera.
8 0
3 years ago
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