"decreasing the distance of the space shuttle from Earth"
F = Gm(1)m(2)/R²
where R is the distance between the 2 objects, as it decreases, the force increases.
Answer:
C. 3,200
Explanation:
MA= F out/ F in.
multiply F in on both sides to cancel it out so you can solve for F out.
Fin*MA=F out
400 * 8 = F out
3,200= F out
The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it. Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.
12 seconds at an average speed of 9 m/s ==> (12 x 9) = 108 meters .
==========================================
That's the way I like to brain it out. If you prefer to use the formula,
the first problem you run into is: You need to remember the formula !
The formula is D = 1/2 a T²
Distance = (1/2 acceleration) x (time in seconds)²
Acceleration = (change in speed) / (time for the change)
= (18 m/s) / (12 sec)
= 1.5 m/s² .
Distance = (1/2 x 1.5 m/s²) x (12 sec)²
= (0.75 m/s²) x (144 sec²) = 108 meters .
Answer:
Speed of air = 1106.38 ft/s
Explanation:
Speed of sound in air with temperature
Here speed is in m/s and T is in celcius scale.
T = 50°F
Substituting
Now we need to convert m/s in to ft/s.
1 m = 3.28 ft
Substituting
Speed of air = 1106.38 ft/s
Answer:
There will be a phase change at the first interface and no phase change at the second interface:
If the film is 1/4 wavelength thick this restriction will hold
The wavelength of the light in oil is 545 nm / 1.45 = 376 nm
376 nm / 4 = 94 nm
"D" is correct
