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3 years ago

2. (1) A piece of rubber is 50 cm long when a weight of

Physics

1 answer:

Harrizon [31]3 years ago

8 0

Answer

By F = -kx {-ve just indicating the sign of the force}

=>35 = k x (85-50) x 10^-2

=>k = 100 N/m

Again by F = -kx

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A student pulls horizontally on a 12 kg box, which then moves horizontally with an acceleration of 0.2 m/s^2. If the student use

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Answer:

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Explanation:

Given;

mass of the crate, m = 100 kg

applied force, F = 250 N

angle of inclination, θ = 45°

coefficient of friction, μ = 0.12

Applied force in y-direction, $F_y = Fsin \theta = 250sin45 = 176.78 \ N$

Applied force in x-direction, $F_x = Fcos \theta = 250cos45 = 176.78 \ N$

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Fk = 0.12 x 803.22

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(a) The net force is given by;

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(b) the velocity of the crate after 5.0 s

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