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mojhsa [17]
3 years ago
13

Sketch the graph of each function

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0
<h2>Answer:</h2>

The graph is a sin wave given in the image

jenyasd209 [6]3 years ago
4 0

Answer:

See diagram

Step-by-step explanation:

First, consider the graph of the parent function y=\cos x. This function has the period 2\pi.

Rewrite the function y=2(1+\cos (x-\frac{\pi}{2})) as y=2+2\cos (x-\frac{\pi}{2}). The graph of this function has the same period of 2\pi, is twice streched and translated \frac{\pi}{2} units to the right and 2 units up graph of the parent function (see diagram).

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Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
Anna71 [15]

Answer by JKismyhusbandbae: B) –10.6

Work/Explanation: Since the sequence slowly gets smaller, it is likely that each term is something added to (subtracted from) the previous term. To get from –7.9 to –8.8, it appears that the first has had –0.9 added to it. Continue adding –0.9 to get that the fourth term is –10.6.

8 0
3 years ago
it takes 8 labours 6days to complete a certain job.how many labours would complete the job in 15 days.​
VashaNatasha [74]

Answer:

Step-by-step explanation:

Required man days to complete the job = 8 * 6

                                                                   = 48 Man Days

Required labors to complete the job by 15 days = 48/15

                                                                               = 3.2

It means, it is required 4 labors can complete the certain work by 15 days

3 0
3 years ago
Solve 34=j−12<br> .<br> j=<br> Find the value of j
Semenov [28]

Answer:

j=46

Step-by-step explanation:

34=j-12

add 12 to 34 to isolate j

the answer to that is 46

j=46

6 0
3 years ago
calculate the means and the standard deviation of the following set of data 4.578g, 4.581g, 4.572g, 4.573g, 4.601g, 4.577g. stat
AfilCa [17]

Answer:

68% Confidence interval  = [4.5752, 4.5848]

95% Confidence interval  = [4.5688, 4.5918]

Step-by-step explanation:

Sample mean (X) = 4.580

Sample Standard Deviation (S) = 0.01065

Sample size (n) = 6

T_{(5)} for alpha/2 0.84 = 1.1037

T_{(5)} for alpha/2 0.975 = 2.5706

68% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}] = [4.5752, 4.5848]

95% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}] = [4.5688, 4.5918]

7 0
3 years ago
(1.75)^2 in expanded form
s2008m [1.1K]

Answer:

1.75 x 1.75

fillerfillerfiller

3 0
2 years ago
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