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Alla [95]
3 years ago
15

An object with a mass of 5.0 kg accelerates 8.0 m/s2 when an unknown force is applied to it. What is the amount of the force?

Chemistry
1 answer:
atroni [7]3 years ago
7 0
The correct amount of force i believe is
f= 40 newton
i got the answer by using the formula below
force = mass x acceleration
f=5kg *8.0 m/s^2


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Explanation:

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How much heat will be given off when 1500 g of water cools down by 20 C? please help and explain:)))
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Answer:

126000J

Explanation:

From the question given, we obtained the following information:

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Identify the factors that govern the speed and direction of a reaction. Check all that apply.
Fiesta28 [93]

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3 years ago
What is the engine piston displacement in liters of an engine whose displacement is listed as 490 in^3?
marishachu [46]

Answer:

490 in^3 = 8.03 L

Explanation:

Given:

The engine displacement = 490 in^3

= 490 in³

To determine the engine piston displacement in liters L;

(NOTE: Both in^3 (in³) and L are units of volume). Hence, to find the engine piston displacement in liters (L), we will convert in^3 to liters (L)

First, we will convert in³ to cm³

Since 1 in = 2.54 cm

∴ 1 in³ = 16.387 cm³

If 1 in³ = 16.387 cm³

Then 490 in³ =  (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³

∴ 490 in³ = 8029.63 cm³

Now will convert cm³ to dm³

(NOTE: 1 L = 1 dm³)

1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm

∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³

If 1 cm³ = 1 × 10⁻³ dm³

Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³

≅ 8.03 dm³

∴ 8029.63 cm³ = 8.03 dm³

Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³

Since 1L = 1 dm³

∴ 8.03 dm³ = 8.03 L

Hence, 490 in³ = 8.03 L

3 0
3 years ago
PLEASE PLEASE BRAINLIEST HELP ME PLEASE SOMEONE VARY SMART PLEASE SOMEONE THAT IS ACE PLEASE OR AN EXPERT OR SOMEONE FROME THE L
ValentinkaMS [17]

Answer:

1: A

2: C

3: D

4: D

5: B

Explanation:

4 0
3 years ago
Read 2 more answers
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